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A master–slave D flip-flop. It responds on the falling edge of the enable input (usually a clock). An implementation of a master–slave D flip-flop that is triggered on the rising edge of the clock. A master–slave D flip-flop is created by connecting two gated D latches in series, and inverting the enable input to one of them. It is called ...
I2C and I3C are also an example of master-slave technology. Modbus uses a master device to initiate connection requests to slave devices. An edge-triggered flip-flop can be created by arranging two gated latches in a master–slave configuration. It is so named because the master latch controls the slave latch's value and forces the slave latch ...
A pulse transition detector is used in flip flops in order to achieve edge triggering in the circuit. It merely converts the clock signal's rising edge to a very narrow pulse. The PTD consists of a delay gate (which delays the clock signal) and the clock signal itself passed through a NAND gate and then inverted.
J-K master-slave flip-flop 14 SN74104: 74x105 1 J-K master-slave flip-flop, J2 and K2 inverted 14 SN74105: 74x106 2 dual J-K negative-edge-triggered flip-flop, preset and clear 16 SN74H106: 74x107 2 dual J-K flip-flop, clear 14 SN74LS107A: 74x108 2 dual J-K negative-edge-triggered flip-flop, preset, common clear and common clock 14 SN74H108 ...
An alternative solution to clock gating is to use Clock Enable (CE) logic on synchronous data path employing the input multiplexer, e.g., for D type flip-flops: using C / Verilog language notation: Dff= CE? D: Q; where: Dff is D-input of D-type flip-flop, D is module information input (without CE input), Q is D-type flip-flop output.
An arrangement of D flip-flops is a classic method for integer-n division. Such division is frequency and phase coherent to the source over environmental variations, including temperature. The easiest configuration is a series where each D flip-flop is a divide-by-2. For a series of three of these, such a system would be a divide-by-8.
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Flip-flop excitation tables [ edit ] In order to complete the excitation table of a flip-flop , one needs to draw the Q(t) and Q(t + 1) for all possible cases (e.g., 00, 01, 10, and 11), and then make the value of flip-flop such that on giving this value, one shall receive the input as Q(t + 1) as desired.