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A solution is composed of a solute being dissolved in a solvent. If you make Kool-Aid, the Kool-Aid crystals are the solute. The water is the solvent, and the delicious Kool-Aid is the solution. The solution is created when the particles of the Kool-Aid crystals diffuse throughout the water. The speed of the diffusion process depends on the temperature of the solvent and the size of the solute ...
An osmole (Osmol) is 1 mol of particles that contribute to the osmotic pressure of a solution. For example, "NaCl" dissociates completely in water to form "Na"^+ ions and "Cl"^- ions. Thus, each mole of "NaCl" becomes two osmoles in solution: one mole of "Na"^+ and one mole of "Cl"^-". A solution of 1 mol/L "NaCl" has an osmolarity of 2 Osmol/L.
In solution (when the ionic compound is dissolved in a liquid solvent - e.g. water), these compounds split up to release the ions and the ions are free to move around as in a liquid. An example is when you dissolve salt (NaCl / Sodium Chloride - an ionic compound) in water. The NaCl splits up into #Na^+# and #Cl^-# ions. The salt is not liquid ...
EXAMPLE 2: How would you make 500 mL of a 1:250 dilution? Solution: "DF" = V_f/V_i V_i = V_f/("DF") ="500 mL"/250 = "2.00 mL" Pipet 2.00 mL of your stock solution into a 500 mL volumetric flask. Add diluent to the mark on the flask (you will have added about 498 mL of water). You now have a 1:250 dilution of your original solution.
Molarity is the concentration of a solution expressed as the number of moles of solute per litre of solution. To get the molarity, you divide the moles of solute by the litres of solution. "Molarity" = "moles of solute"/"litres of solution" For example, a 0.25 mol/L NaOH solution contains 0.25 mol of sodium hydroxide in every litre of solution. To calculate the molarity of a solution, you need ...
A supersaturated solution contains more solute at a given temperature than is needed to form a saturated solution. Increased temperature usually increases the solubility of solids in liquids. For example, the solubility of glucose at 25 °C is 91 g/100 mL of water. The solubility at 50 °C is 244 g/100 mL of water. If we add 100 g of glucose to 100 mL water at 25 °C, 91 g dissolve. Nine grams ...
Yes, consisting of mainly nitrogen, followed by oxygen and then miscellaneous gases. The term "air" is a solution of many elements. As you can see, more than 3/4 of the atmosphere consists of nitrogen. Air is more concentrated near the Earth's surface and "thins out" as the altitude increases, in which there is less oxygen. "Nitrogen accounts for 78% of the atmosphere, oxygen 21% and argon 0.9 ...
The solution set of this new equation is; #{-5, 5}#. The #-5# is an extraneous solution introduced by squaring the two expressions. Square both sides of #x-1=4# to get #x^2-2x+1=16# which is equivalent to #x^2-2x-15=0#. and, rewriting the left, #(x+3)(x-5)=0#. So the solution set is #{-3, 5}#. This time, it is #-3#, that is the extra solution.
Solid solution is mixture of two crystalline solids. The mixing is done by combining two solids after melting them into liquids and then cooling the result to form a new solid. Examples such ...
For example, suppose you are asked to solve: (x^2-4)/(x-2) = 0 Multiplying both sides of the equation by (x-2) you get: x^2-4 = 0 which has solutions x=2 and x=-2 The value x=-2 is a solution of the original equation, but x=2 is not since it results in division by 0.