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The birthday problem can be generalized as follows: Given n random integers drawn from a discrete uniform distribution with range [1,d], what is the probability p(n; d) that at least two numbers are the same? (d = 365 gives the usual birthday problem.) [17] The generic results can be derived using the same arguments given above.
A birthday attack is a bruteforce collision attack that exploits the mathematics behind the birthday problem in probability theory. This attack can be used to abuse communication between two or more parties. The attack depends on the higher likelihood of collisions found between random attack attempts and a fixed degree of permutations ...
Your math basis is incorrect. The probability that 365 people have distinct birthdays is 365!/365^365. (1/365! is the probability that you take 365 people with distinct birthdays and, picking them one at a time, correctly pick them in birthday order).
The birthday problem asks, for a set of n randomly chosen people, what is the probability that some pair of them will have the same birthday? The problem itself is mainly concerned with counterintuitive probabilities, but we can also tell by the pigeonhole principle that among 367 people, there is at least one pair of people who share the same ...
The probability that this person's birthday falls on a different day is then equal to the complement =. It is easier now to consider the complementary question: What is the probability q N {\displaystyle q_{N}} that none among N {\displaystyle N} randomly selected persons has a given birthday D.
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Pages in category "Probability theory paradoxes" The following 21 pages are in this category, out of 21 total. ... Birthday problem; Borel–Kolmogorov paradox; Boy ...
Plus, probability gives us simple problems whose solutions are totally counterintuitive." #22. Image credits: memeformathematicians #23. ... "For example, the birthday paradox. But all they are is ...