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  2. Pumping lemma for regular languages - Wikipedia

    en.wikipedia.org/wiki/Pumping_lemma_for_regular...

    The pumping lemma is often used to prove that a particular language is non-regular: a proof by contradiction may consist of exhibiting a string (of the required length) in the language that lacks the property outlined in the pumping lemma. Example: The language = {:} over the alphabet = {,} can be shown to be non-regular as follows:

  3. Pumping lemma for context-free languages - Wikipedia

    en.wikipedia.org/wiki/Pumping_lemma_for_context...

    The pumping lemma for context-free languages (called just "the pumping lemma" for the rest of this article) describes a property that all context-free languages are guaranteed to have. The property is a property of all strings in the language that are of length at least p {\displaystyle p} , where p {\displaystyle p} is a constant—called the ...

  4. Ogden's lemma - Wikipedia

    en.wikipedia.org/wiki/Ogden's_lemma

    Ogden's lemma is often stated in the following form, which can be obtained by "forgetting about" the grammar, and concentrating on the language itself: If a language L is context-free, then there exists some number (where p may or may not be a pumping length) such that for any string s of length at least p in L and every way of "marking" p or more of the positions in s, s can be written as

  5. Context-free grammar - Wikipedia

    en.wikipedia.org/wiki/Context-free_grammar

    A reduction can be demonstrated to this problem from the well-known undecidable problem of determining whether a Turing machine accepts a particular input (the halting problem). The reduction uses the concept of a computation history, a string describing an entire computation of a Turing machine. A CFG can be constructed that generates all ...

  6. Myhill–Nerode theorem - Wikipedia

    en.wikipedia.org/wiki/Myhill–Nerode_theorem

    (1) If is regular, construct a minimal DFA to accept it. Clearly, if x , y {\displaystyle x,y} end up in the same state after running through the DFA, then x ∼ L y {\displaystyle x\sim _{L}y} , thus the number of equivalence classes of ∼ L {\displaystyle \sim _{L}} is at most the number of DFA states, which must be finite.

  7. Chomsky normal form - Wikipedia

    en.wikipedia.org/wiki/Chomsky_normal_form

    To convert a grammar to Chomsky normal form, a sequence of simple transformations is applied in a certain order; this is described in most textbooks on automata theory. [4]: 87–94 [5] [6] [7] The presentation here follows Hopcroft, Ullman (1979), but is adapted to use the transformation names from Lange, Leiß (2009).

  8. Talk:Pumping lemma for regular languages - Wikipedia

    en.wikipedia.org/wiki/Talk:Pumping_lemma_for...

    Hi Jochen Burghardt, the example of a non-regular language given to satisfy the non-generalised Pumping Lemma does not satisfy it. For example the word abc can be pumped down to bc which is not in the given language. This is a deep flaw in the example that cannot be easily fixed - as it relies on m ≥ 1.

  9. Pumping lemma - Wikipedia

    en.wikipedia.org/wiki/Pumping_lemma

    Pumping lemma for context-free languages, the fact that all sufficiently long strings in such a language have a pair of substrings that can be repeated arbitrarily many times, usually used to prove that certain languages are not context-free; Pumping lemma for indexed languages; Pumping lemma for regular tree languages