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If the tree is not empty, then we go down the root, and recursively go down the tree searching for the location to insert the new node. This traversal is guided by the comparison function. In this case, the node always replaces a NULL reference (left or right) of an external node in the tree i.e., the node is either made a left-child or a right ...
To insert into a 3-node, more work may be required depending on the location of the 3-node. If the tree consists only of a 3-node, the node is split into three 2-nodes with the appropriate keys and children. Insertion of a number in a 2–3 tree for 3 possible cases. If the target node is a 3-node whose parent is a 2-node, the key is inserted ...
But I agree, it would be interesting to state an algorithm how to do it. A simple one might be to create an empty tree, then walk the original unbalanced tree in-order, and insert each node into the new tree, using the AVL-insert. That should take O(n*log n). --Allefant 14:24, 24 November 2006 (UTC)
Weak AVL rule: all rank differences are 1 or 2, and all leaf nodes have rank 0. Note that weak AVL tree generalizes the AVL tree by allowing for 2,2 type node. A simple proof shows that a weak AVL tree can be colored in a way that represents a red-black tree. So in a sense, weak AVL tree combines the properties of AVL tree and red-black tree.
To insert a value, we start at the root of the 2–3–4 tree: If the current node is a 4-node: Remove and save the middle value to get a 3-node. Split the remaining 3-node up into a pair of 2-nodes (the now missing middle value is handled in the next step). If this is the root node (which thus has no parent):
This unsorted tree has non-unique values (e.g., the value 2 existing in different nodes, not in a single node only) and is non-binary (only up to two children nodes per parent node in a binary tree). The root node at the top (with the value 2 here), has no parent as it is the highest in the tree hierarchy.
The priority search tree is used to store a set of 2-dimensional points ordered by priority and by a key value. This is accomplished by creating a hybrid of a priority queue and a binary search tree. The result is a tree where each node represents a point in the original dataset. The point contained by the node is the one with the lowest priority.
To insert a value x into a splay tree: Insert x as with a normal binary search tree. Perform a splay on x. As a result, the newly inserted node x becomes the root of the tree. Alternatively: Use the split operation to split the tree at the value of x to two sub-trees: S and T.