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In physics, Hooke's law is an empirical law which states that the force (F) needed to extend or compress a spring by some distance (x) scales linearly with respect to that distance—that is, F s = kx, where k is a constant factor characteristic of the spring (i.e., its stiffness), and x is small compared to the total possible deformation of the spring.
The following table gives formula for the spring that is equivalent to a system of two springs, in series or in parallel, whose spring constants are and . [1] The compliance c {\displaystyle c} of a spring is the reciprocal 1 / k {\displaystyle 1/k} of its spring constant.)
The rate or spring constant of a spring is the change in the force it exerts, divided by the change in deflection of the spring. That is, it is the gradient of the force versus deflection curve. An extension or compression spring's rate is expressed in units of force divided by distance, for example or N/m or lbf/in.
Pulling the spring to a greater length causes it to exert a force that brings the spring back toward its equilibrium length. The amount of force can be determined by multiplying the spring constant, characteristic of the spring, by the amount of stretch, also known as Hooke's Law. Another example is of a pendulum.
The sensitivity of the instrument comes from the weak spring constant of the fiber, so a very weak force causes a large rotation of the bar. In Coulomb's experiment, the torsion balance was an insulating rod with a metal-coated ball attached to one end, suspended by a silk thread.
Jun-ichi Ueda and Yoshiro Sadamoto have found [1] that as increases beyond , the effective mass of a spring in a vertical spring-mass system becomes smaller than Rayleigh's value and eventually reaches negative values at about . This unexpected behavior of the effective mass can be explained in terms of the elastic after-effect (which is the ...
It is calculated using the following equation: ˙ = where is the mid-radius value and ˙ is the strain rate. The viscosity of the sample is then calculated using the following equation: η = F π R 2 ϵ ˙ {\displaystyle \eta ={\frac {F}{\pi R^{2}{\dot {\epsilon }}}}} where η {\displaystyle \eta } is the sample viscosity, and F {\displaystyle ...
For a stretched spring fixed at one end obeying Hooke's law, the elastic potential energy is Δ E p = 1 2 k ( r 2 − r 1 ) 2 {\displaystyle \Delta E_{p}={\frac {1}{2}}k(r_{2}-r_{1})^{2}} where r 2 and r 1 are collinear coordinates of the free end of the spring, in the direction of the extension/compression, and k is the spring constant.