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By definition, 36 AWG is 0.005 inches in diameter, and 0000 AWG is 0.46 inches in diameter. The ratio of these diameters is 1:92, and there are 40 gauge sizes from 36 to 0000, or 39 steps. Because each successive gauge number increases cross sectional area by a constant multiple, diameters vary geometrically.
A table of the gauge numbers and wire diameters is shown below. [1] [2] The basis of the system is the thou (or mil in US English), or 0.001 in. Sizes are specified as wire diameters, stated in thou and tenths of a thou (mils and tenths). The wire diameter diminishes with increasing size number.
No. 7/0, the largest size, is 0.50 inches (500 mils or 12.7 mm) in diameter (250 000 circular mils in cross-sectional area), and the smallest, No. 50, is 0.001 inches (1 mil or 25.4 μm) in diameter (1 circular mil [cross-sectional area] or 0.7854 millionths of a square inch).
comparison wire gauge sizes: Image title: Comparison of SWG (red), AWG (blue) and IEC 60228 (black) wire gauge sizes from 0.03 to 200 mm² to scale on a 1 mm grid, by CMG Lee. In the SVG file, hover over an item to highlight it. Width: 100%: Height: 100%
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Also, the size of the aluminum wire needs to be larger compared to copper wire used for the same circuit due to the increased resistance of the aluminum alloys. For example, a 15 A branch circuit supplying standard lighting fixtures can be installed with either #14 AWG copper building wire or #12 AWG aluminum building wire according to the NEC ...
For example, one common wire size used in the NEC has a conductor diameter of 0.5 inches, or 500 mils, and thus a cross-section of = circular mils, written as 250 kcmil or 250 MCM, which is the first size larger than 0000 AWG used within the NEC.
Comparison of SWG (red), AWG (blue) and IEC 60228 (black) wire gauge sizes from 0.03 to 200 mm² to scale on a 1 mm grid – in the SVG file, hover over a size to highlight it. In engineering applications, it is often most convenient to describe a wire in terms of its cross-section area, rather than its diameter, because the cross section is directly proportional to its strength and weight ...