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  2. Heine–Borel theorem - Wikipedia

    en.wikipedia.org/wiki/Heine–Borel_theorem

    If a set is closed and bounded, then it is compact. If a set S in R n is bounded, then it can be enclosed within an n-box = [,] where a > 0. By the lemma above, it is enough to show that T 0 is compact. Assume, by way of contradiction, that T 0 is not compact.

  3. Bolzano–Weierstrass theorem - Wikipedia

    en.wikipedia.org/wiki/Bolzano–Weierstrass_theorem

    This form of the theorem makes especially clear the analogy to the Heine–Borel theorem, which asserts that a subset of is compact if and only if it is closed and bounded. In fact, general topology tells us that a metrizable space is compact if and only if it is sequentially compact, so that the Bolzano–Weierstrass and Heine–Borel theorems ...

  4. Compact space - Wikipedia

    en.wikipedia.org/wiki/Compact_space

    The interval C = (2, 4) is not compact because it is not closed (but bounded). The interval B = [0, 1] is compact because it is both closed and bounded. In mathematics, specifically general topology, compactness is a property that seeks to generalize the notion of a closed and bounded subset of Euclidean space. [1]

  5. Equicontinuity - Wikipedia

    en.wikipedia.org/wiki/Equicontinuity

    Let X be a compact Hausdorff space, and equip C(X) with the uniform norm, thus making C(X) a Banach space, hence a metric space. Then Arzelà–Ascoli theorem states that a subset of C(X) is compact if and only if it is closed, uniformly bounded and equicontinuous.

  6. Bounded set - Wikipedia

    en.wikipedia.org/wiki/Bounded_set

    The metric space (M, d) is a bounded metric space (or d is a bounded metric) if M is bounded as a subset of itself. Total boundedness implies boundedness. For subsets of R n the two are equivalent. A metric space is compact if and only if it is complete and totally bounded. A subset of Euclidean space R n is compact if and only if it is closed and

  7. Totally bounded space - Wikipedia

    en.wikipedia.org/wiki/Totally_bounded_space

    [0, 1] 2 is a totally bounded space because for every ε > 0, the unit square can be covered by finitely many open discs of radius ε. A metric space (,) is totally bounded if and only if for every real number >, there exists a finite collection of open balls of radius whose centers lie in M and whose union contains M.

  8. Compactification (mathematics) - Wikipedia

    en.wikipedia.org/wiki/Compactification_(mathematics)

    It is possible to turn the real line into a compact space by adding a single "point at infinity" which we will denote by ∞. The resulting compactification is homeomorphic to a circle in the plane (which, as a closed and bounded subset of the Euclidean plane, is compact). Every sequence that ran off to infinity in the real line will then ...

  9. Real analysis - Wikipedia

    en.wikipedia.org/wiki/Real_analysis

    (In the context of real analysis, these notions are equivalent: a set in Euclidean space is compact if and only if it is closed and bounded.) Briefly, a closed set contains all of its boundary points , while a set is bounded if there exists a real number such that the distance between any two points of the set is less than that number.