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  2. Contrast (statistics) - Wikipedia

    en.wikipedia.org/wiki/Contrast_(statistics)

    A contrast is defined as the sum of each group mean multiplied by a coefficient for each group (i.e., a signed number, c j). [10] In equation form, = ¯ + ¯ + + ¯ ¯, where L is the weighted sum of group means, the c j coefficients represent the assigned weights of the means (these must sum to 0 for orthogonal contrasts), and ¯ j represents the group means. [8]

  3. Abelian and Tauberian theorems - Wikipedia

    en.wikipedia.org/wiki/Abelian_and_tauberian_theorems

    The original examples are Abel's theorem showing that if a series converges to some limit then its Abel sum is the same limit, and Tauber's theorem showing that if the Abel sum of a series exists and the coefficients are sufficiently small (o(1/n)) then the series converges to the Abel sum. More general Abelian and Tauberian theorems give ...

  4. Kahan summation algorithm - Wikipedia

    en.wikipedia.org/wiki/Kahan_summation_algorithm

    The algorithm performs summation with two accumulators: sum holds the sum, and c accumulates the parts not assimilated into sum, to nudge the low-order part of sum the next time around. Thus the summation proceeds with "guard digits" in c , which is better than not having any, but is not as good as performing the calculations with double the ...

  5. Zero-sum problem - Wikipedia

    en.wikipedia.org/wiki/Zero-sum_problem

    Explicitly this says that any multiset of 2n − 1 integers has a subset of size n the sum of whose elements is a multiple of n, but that the same is not true of multisets of size 2n − 2. (Indeed, the lower bound is easy to see: the multiset containing n − 1 copies of 0 and n − 1 copies of 1 contains no n-subset summing to a multiple of n.)

  6. Inclusion–exclusion principle - Wikipedia

    en.wikipedia.org/wiki/Inclusion–exclusion...

    In the given example, there are 12 = 2(3!) permutations with property P 1, 6 = 3! permutations with property P 2 and no permutations have properties P 3 or P 4 as there are no restrictions for these two elements. The number of permutations satisfying the restrictions is thus: 4! − (12 + 6 + 0 + 0) + (4) = 24 − 18 + 4 = 10.

  7. Man Who Stabbed His Father 50 Times Reportedly Tells ... - AOL

    www.aol.com/man-stabbed-father-50-times...

    Jeffrey Goedde, 41, handed himself into the Jefferson County Sheriff’s Office on Wednesday, Dec. 18, according to court documents seen by PEOPLE

  8. Neumann series - Wikipedia

    en.wikipedia.org/wiki/Neumann_series

    Then, using the Neumann series identity that = = if the appropriate norm condition on = is satisfied, = (()) = = (). Since these terms shrink with increasing k , {\displaystyle k,} given the conditions on the norm, then truncating the series at some finite n {\displaystyle n} may give a practical approximation to the inverse matrix:

  9. More than 1 million will pack Times Square in NYC tonight ...

    www.aol.com/more-1-million-pack-times-195747538.html

    "We expect rain to move into midtown Manhattan sometime between 7 and 9 p.m. on New Year's Eve and continue until 11 p.m. to 1 a.m. that night," said Alex Duff, an AccuWeather meteorologist, in an ...