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A cartesian equation of a curve is simply finding the single equation of this curve in a standard form where xs and ys are the only variables. To find this equation, you need to solve the parametric equations simultaneously: If y = 4t, then divide both sides by 4 to find (1/4)y = t. This newly found value of t can be substituted into the ...
In some cases, 't' may be raised to a power in either equation. It is usually quicker to start by rearranging the lowest order equation for 't' and substituting it into the higher order equation. However, some questions may involve trigonometric functions e.g. x = sin^2(t) and y = cos(2t).
Find, using calculus, the x coordinate of the turning point of the curve with equation y=e^3x cos 4 Answered by Urszula W. Find the turning point of y = x + 1 + 4/x2 and describe the nature of the turning point
Note: I have a screenshot of the question that I should be able to add to the work space. Q5 C4 June 2014 Edexcel.x + y = 2sqrt(3) cos tStart with x = 4 cos ( t +...
If on the other hand you know the Cartesian equation of a plane, which looks like (ax)+(by)+(cz)=0, then the vector (a,b,c) is a normal vector! Answered by Fionn K. • Maths tutor 19098 Views
Reminder - a cartesian equation is written in terms of x and y (e.g. y = 2x + 3) while parametric equations are written with x and y separately in terms of t. Example: Find the cartesian equation of the curve given by these parametric equations: x = 2t + 1, y = 1/t (where t is not equal to zero) First make t the subject in one of the equations.
A curve is given by the equation y = (1/3)x^3 -4x^2 +12x -19. Find the co-ordinates of any stationary points and determine whether they are maximum or minimun points. Answered by Joseph C.
It can be shown that the equation of any plane can be given by r.n=a.n, where r = xi + yj + zk, n is a direction vector normal to the plane, and a is any point vector on the plane. a can be found easily (three points are already given in the question for us to choose from – in this case we’ll choose point A for simplicity).
A Curve has parametric equation x=2sin(t), y= 1+cos(2t), -pi/2<=t<=pi/2. a) Find dy/dx when t=pi/3. b) Find the Cartesian equation for the curve in form y=f(x), -k<=x<=k.
e^x= t+3 t= e^x -3therefore y= 1/e^x-3+5y= 1/e^x+2 One-to-one online tuition can be a great way to brush up on your. Maths knowledge.