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In geometry, a triangular prism or trigonal prism [1] is a prism with 2 triangular bases. If the edges pair with each triangle's vertex and if they are perpendicular to the base, it is a right triangular prism. A right triangular prism may be both semiregular and uniform. The triangular prism can be used in constructing another polyhedron.
To get the surface area of a triangular prism, you need to find the base area(0.5*bh) of the triangle. This is known as A1 in the following formula. The rectanges are known as A2, A3, and A4 in this formula. The formula for an equilateral triangular base in the prism is: A1×2+A2×3. The formula for an isosceles triangular base in the prism is:
The surface area of a right prism is: +, where B is the area of the base, h the height, and P the base perimeter. The surface area of a right prism whose base is a regular n-sided polygon with side length s, and with height h, is therefore: = +.
An augmented triangular prism with edge length has a surface area, calculated by adding six equilateral triangles and two squares' area: [2] +. Its volume can be obtained by slicing it into a regular triangular prism and an equilateral square pyramid, and adding their volume subsequently: [2] +.
A triaugmented triangular prism with edge length has surface area [10], the area of 14 equilateral triangles. Its volume, [10] +, can be derived by slicing it into a central prism and three square pyramids, and adding their volumes.
To calculate the formula for the surface area and volume of a gyrobifastigium with regular faces and with edge length , one may adapt the corresponding formulae for the triangular prism. Its surface area can be obtained by summing the area of four equilateral triangles and four squares, whereas its volume by slicing it off into two triangular ...
A sphere of radius r has surface area 4πr 2.. The surface area (symbol A) of a solid object is a measure of the total area that the surface of the object occupies. [1] The mathematical definition of surface area in the presence of curved surfaces is considerably more involved than the definition of arc length of one-dimensional curves, or of the surface area for polyhedra (i.e., objects with ...
The area of a triangle can be demonstrated, for example by means of the congruence of triangles, as half of the area of a parallelogram that has the same base length and height. A graphic derivation of the formula T = h 2 b {\displaystyle T={\frac {h}{2}}b} that avoids the usual procedure of doubling the area of the triangle and then halving it.