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another syntax to grep a string in all files on a Linux system recursively. grep -irn "string". a breakdown of the command. -r, --recursive. indicates a recursive search that finds the specified string in the given directory and sub directory looking for the specific string in files, binary, etc. -i, --ignore-case.
grep -nr yourString* . This actually searches the string "yourStrin" and "g" 0 or many times. So the proper way to do it is: grep -nr \w*yourString\w* . This command searches the string with any character before and after on the current folder. edited May 11, 2013 at 4:32.
This grep command will give you a precise result when you are searching for specific text on Linux - grep -inRsH "Text to be searched" /path/to/dir (it can be '.') i stands for ignore case distinctions. R stands for recursive and it also include symlinks. It is better to use 'R' instead of 'r' n stands for "it will print line number".
If I read your question carefully, you ask to "grep to search the current directory for any and all files containing the string "hello" and display only .h and .cc files". So to meet your precise requirements here is my submission: This displays the file names: grep -lR hello * | egrep '(cc|h)$' ...and this display the file names and contents:
73. You could even do it like this: Example. grep -rl 'windows' ./ | xargs sed -i 's/windows/linux/g'. This will search for the string ' windows ' in all files relative to the current directory and replace ' windows ' with ' linux ' for each occurrence of the string in each file. edited Apr 27, 2020 at 12:59.
@topek: Good point -- if you have any .cpp/.h files in your current directory, then the shell will expand the glob before invoking grep, so you'll end up with a command line like grep pattern -r --include=foo.cpp --include=bar.h rootdir, which will only search files named foo.cpp or bar.h. If you don't have any files that match the glob in the ...
To understand sed command, we have to build it step by step. Here is your original text. user@linux:~$ echo "Here is a String" Here is a String user@linux:~$ Let's try to remove Here string with substition option in sed. user@linux:~$ echo "Here is a String" | sed 's/Here //' is a String user@linux:~$
grep -x -f A.txt B.txt EDIT: If you don't want grep's regex capabilities and need to treat search pattern as fixed-strings then use -F switch as: grep -xF -f A.txt B.txt -x, --line-regexp Only input lines selected against an entire fixed string or regular expression are considered to be matching lines.
Trying to find general answer: Generate a list with the result of the first grep: grep pattern | awk -F':' ' {print $1}'. Second grep into the list of files like here. xargs grep -i pattern. apply this cascading filter the times you need just adding awk to get only the filenames and xargs to pass the filenames to grep -i.
1141. You can do it using -v (for --invert-match) option of grep as: grep -v "unwanted_word" file | grep XXXXXXXX. grep -v "unwanted_word" file will filter the lines that have the unwanted_word and grep XXXXXXXX will list only lines with pattern XXXXXXXX. EDIT: From your comment it looks like you want to list all lines without the unwanted_word.