Search results
Results from the WOW.Com Content Network
The ideal gas equation can be rearranged to give an expression for the molar volume of an ideal gas: = = Hence, for a given temperature and pressure, the molar volume is the same for all ideal gases and is based on the gas constant: R = 8.314 462 618 153 24 m 3 ⋅Pa⋅K −1 ⋅mol −1, or about 8.205 736 608 095 96 × 10 −5 m 3 ⋅atm⋅K ...
Download as PDF; Printable version; In other projects ... Methane: 2.253 0.04278 Methanol: 9.649 ... (where kmol is kilomoles = 1000 moles) References
0.1 × ( 12 ÷ 8 ) = 0.15 grain per dscf when corrected to a gas having a specified reference CO 2 content of 12 volume %. Notes: Although ppmv and grains per dscf have been used in the above examples, concentrations such as ppbv (i.e., parts per billion by volume), volume percent, grams per dscm and many others may also be used.
The van der Waals equation of state may be written as (+) =where is the absolute temperature, is the pressure, is the molar volume and is the universal gas constant.Note that = /, where is the volume, and = /, where is the number of moles, is the number of particles, and is the Avogadro constant.
Here = / and = /, with = + (so that + =), are the mole fractions of the two fluid substances. Adding the equations for the two fluids shows that p ≠ p 1 + p 2 {\displaystyle p\neq p_{1}+p_{2}} , although for v {\displaystyle v} sufficiently large p ≈ p 1 + p 2 {\displaystyle p\approx p_{1}+p_{2}} with equality holding in the ideal gas limit.
1.1 kJ/mol Std entropy change of fusion, Δ fus S o: 12.1 J/(mol·K) Std enthalpy change of vaporization, Δ vap H o: 8.17 kJ/mol Std entropy change of vaporization, Δ vap S o? J/(mol·K) Solid properties Std enthalpy change of formation, Δ f H o solid? kJ/mol Standard molar entropy, S o solid? J/(mol K) Heat capacity, c p? J/(mol K) Liquid ...
File:Densities of compressed liquid methane, and the equation of state (IA jresv76An2p81).pdf
The standard unit is the meter cubed per kilogram (m 3 /kg or m 3 ·kg −1). Sometimes specific volume is expressed in terms of the number of cubic centimeters occupied by one gram of a substance. In this case, the unit is the centimeter cubed per gram (cm 3 /g or cm 3 ·g −1). To convert m 3 /kg to cm 3 /g, multiply by 1000; conversely ...