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  2. Clearing denominators - Wikipedia

    en.wikipedia.org/wiki/Clearing_denominators

    The simplified equation is not entirely equivalent to the original. For when we substitute y = 0 and z = 0 in the last equation, both sides simplify to 0, so we get 0 = 0 , a mathematical truth. But the same substitution applied to the original equation results in x /6 + 0/0 = 1 , which is mathematically meaningless .

  3. Lentz's algorithm - Wikipedia

    en.wikipedia.org/wiki/Lentz's_algorithm

    This method was an improvement compared to other methods because it started from the beginning of the continued fraction rather than the tail, had a built-in check for convergence, and was numerically stable. The original algorithm uses algebra to bypass a zero in either the numerator or denominator. [5]

  4. Greedy algorithm for Egyptian fractions - Wikipedia

    en.wikipedia.org/wiki/Greedy_algorithm_for...

    The simplest fraction3 / y ⁠ with a three-term expansion is ⁠ 3 / 7 ⁠. A fraction ⁠ 4 / y ⁠ requires four terms in its greedy expansion if and only if y ≡ 1 or 17 (mod 24), for then the numerator −y mod x of the remaining fraction is 3 and the denominator is 1 (mod 6). The simplest fraction ⁠ 4 / y ⁠ with a four-term ...

  5. Elementary algebra - Wikipedia

    en.wikipedia.org/wiki/Elementary_algebra

    For example, taking the statement x + 1 = 0, if x is substituted with 1, this implies 1 + 1 = 2 = 0, which is false, which implies that if x + 1 = 0 then x cannot be 1. If x and y are integers, rationals, or real numbers, then xy = 0 implies x = 0 or y = 0. Consider abc = 0. Then, substituting a for x and bc for y, we learn a = 0 or bc = 0.

  6. Partial fraction decomposition - Wikipedia

    en.wikipedia.org/wiki/Partial_fraction_decomposition

    In algebra, the partial fraction decomposition or partial fraction expansion of a rational fraction (that is, a fraction such that the numerator and the denominator are both polynomials) is an operation that consists of expressing the fraction as a sum of a polynomial (possibly zero) and one or several fractions with a simpler denominator. [1]

  7. Irreducible fraction - Wikipedia

    en.wikipedia.org/wiki/Irreducible_fraction

    In the second step, they were divided by 3. The final result, ⁠ 4 / 3 ⁠, is an irreducible fraction because 4 and 3 have no common factors other than 1. The original fraction could have also been reduced in a single step by using the greatest common divisor of 90 and 120, which is 30. As 120 ÷ 30 = 4, and 90 ÷ 30 = 3, one gets

  8. Continued fraction factorization - Wikipedia

    en.wikipedia.org/wiki/Continued_fraction...

    The continued fraction method is based on Dixon's factorization method. It uses convergents in the regular continued fraction expansion of , +. Since this is a quadratic irrational, the continued fraction must be periodic (unless n is square, in which case the factorization is obvious).

  9. Continued fraction - Wikipedia

    en.wikipedia.org/wiki/Continued_fraction

    For the folded general continued fractions of both expressions, the rate convergence μ = (3 − √ 8) 2 = 17 − √ 288 ≈ 0.02943725, hence ⁠ 1 / μ ⁠ = (3 + √ 8) 2 = 17 + √ 288 ≈ 33.97056, whose common logarithm is 1.531... ≈ ⁠ 26 / 17 ⁠ > ⁠ 3 / 2 ⁠, thus adding at least three digits per two terms. This is because the ...

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