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  2. SOLUTION: If x = -2 and y = square root 12 , then 2(3x3 + 2y2)

    www.algebra.com/algebra/homework/Radicals/Radicals.faq.question.702842.html

    Question 702842: If x = -2 and y = square root 12 , then 2(3x3 + 2y2) = Answer by jim_thompson5910(35256) ( Show Source ): You can put this solution on YOUR website!

  3. SOLUTION: how do you rationalize the square root of 1/12

    www.algebra.com/algebra/homework/Square-cubic-other-roots/Square-cubic-other...

    Answer by jsmallt9 (3758) ( Show Source ): You can put this solution on YOUR website! The easiest way to rationalize this is to turn the denominator into a perfect square. So we want to turn the 12 into a perfect square. The obvious thing to do would be to multiply the numerator and denominator by 12. This will definitely work.

  4. square root of 48 - sq. root of 12 - Algebra Homework Help

    www.algebra.com/algebra/homework/Square-cubic-other-roots/Square-cubic-other...

    Algebra -> Square-cubic-other-roots-> SOLUTION: I am stuck on correct answer for: square root of 48 - sq. root of 12 = I am not using a specific book.

  5. SOLUTION: Square root of 12x^3 - Algebra Homework Help

    www.algebra.com/algebra/homework/equations/Equations.faq.question.36156.html

    Answer by stanbon (75887) ( Show Source ): You can put this solution on YOUR website! Square root of 12x^3. Break 12x^3 into two factors making the 1st factor. the largest possible perfect square: for example. 12x^3 = (4x^2) (3x) Then sqrt [12x^3]=sqrt [ (4x^2) (3x)] Rewrite as [sqrt (4x^2)] [sqrt (3x)] Since the 4x^2 is a perfect square you ...

  6. SOLUTION: (3 - 2 Square root of 12) squared - Algebra Homework...

    www.algebra.com/algebra/homework/Radicals/Radicals.faq.question.242155.html

    You can put this solution on YOUR website! (3 - 2 Square root of 12) squared 3-2SQRT12 3-2SQRT12-----9-6SQRT12-6SQRT12+4*12

  7. SOLUTION: Did I do this equation right? 3 sqrt of 12 + 2 sqrt of...

    www.algebra.com/algebra/homework/Square-cubic-other-roots/Square-cubic-other...

    Note: If you need help with simplifying square roots, check out this solver. Multiply 3 and 2 to get 6. Since we have the common term , we can combine like terms Factor out the GCF Combine like terms. So simplifies to . In other words,

  8. SOLUTION: z varies jointly as the square root of the product of x...

    www.algebra.com/algebra/homework/coordinate/Linear-systems.faq.question...

    Question 1008638: z varies jointly as the square root of the product of x and y. If z is equal to 3 when x is equal to 3 and y is equal to 12,find x when z is equal to 6 and y is equal to 64. Answer by fractalier(6550) (Show Source):

  9. SOLUTION: how do you solve... 12 divided by the square root of 2

    www.algebra.com/algebra/homework/Radicals/Radicals.faq.question.492641.html

    You can put this solution on YOUR website! 12/sqrt (2) = sqrt (144)/sqrt (2) = sqrt (72) = sqrt (9)*sqrt (4)*sqrt (2) = 3*2*sqrt (2) = 6*sqrt (2) Basically you first take 12 and put that it terms of a square root: 12 squared equals 144 so 12 = sqrt (144). Then, once you have all your terms in square root form you can do basic division to get ...

  10. SOLUTION: Simplify assume that all variables are nonnegative real...

    www.algebra.com/algebra/homework/Polynomials-and-rational-expressions/...

    The goal of simplifying expressions with square roots is to factor the radicand into a product of two numbers. One of these two numbers must be a perfect square. When you take the square root of this perfect square, you will get a rational number.

  11. SOLUTION: name all sets fo numbers to which each real number...

    www.algebra.com/algebra/homework/real-numbers/real-numbers.faq.question.690261...

    Question 690261: name all sets fo numbers to which each real number belongs. -12 and square root of 11. Answer by tommyt3rd (5050) ( Show Source ): You can put this solution on YOUR website! "name all sets" ... is problematic, so I need to answer in a somewhat general way. -12 is a negative integer so it belongs to any set for which the ...