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  2. Repeating decimal - Wikipedia

    en.wikipedia.org/wiki/Repeating_decimal

    Every terminating decimal representation can be written as a decimal fraction, a fraction whose denominator is a power of 10 (e.g. 1.585 = ⁠ 1585 / 1000 ⁠); it may also be written as a ratio of the form ⁠ k / 2 n ·5 m ⁠ (e.g. 1.585 = ⁠ 317 / 2 3 ·5 2 ⁠).

  3. Cubic equation - Wikipedia

    en.wikipedia.org/wiki/Cubic_equation

    For solving the cubic equation x 3 + m 2 x = n where n > 0, Omar Khayyám constructed the parabola y = x 2 /m, the circle that has as a diameter the line segment [0, n/m 2] on the positive x-axis, and a vertical line through the point where the circle and the parabola intersect above the x-axis.

  4. Algebraic expression - Wikipedia

    en.wikipedia.org/wiki/Algebraic_expression

    The process of transforming an irrational fraction to a rational fraction is known as rationalization. Every irrational fraction in which the radicals are monomials may be rationalized by finding the least common multiple of the indices of the roots, and substituting the variable for another variable with the least common multiple as exponent.

  5. Calculator input methods - Wikipedia

    en.wikipedia.org/wiki/Calculator_input_methods

    Note the formula on the dot-matrix line above and the answer on the seven-segment line below, as well as the arrow keys allowing the entry to be reviewed and edited. This calculator program has accepted input in infix notation, and returned the answer 3 , 8 6 ¯ {\displaystyle 3{\text{,}}8{\overline {6}}} .

  6. Periodic continued fraction - Wikipedia

    en.wikipedia.org/wiki/Periodic_continued_fraction

    The proof is straightforward. From the fraction itself, one can construct the quadratic equation with integral coefficients that x must satisfy. Lagrange proved the converse of Euler's theorem: if x is a quadratic irrational, then the regular continued fraction expansion of x is periodic. [4]

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  8. Solving quadratic equations with continued fractions - Wikipedia

    en.wikipedia.org/wiki/Solving_quadratic...

    By applying the fundamental recurrence formulas we may easily compute the successive convergents of this continued fraction to be 1, 3/2, 7/5, 17/12, 41/29, 99/70, 239/169, ..., where each successive convergent is formed by taking the numerator plus the denominator of the preceding term as the denominator in the next term, then adding in the ...

  9. Formulas for generating Pythagorean triples - Wikipedia

    en.wikipedia.org/wiki/Formulas_for_generating...

    Michael Stifel published the following method in 1544. [3] [4] Consider the sequence of mixed numbers,,,, … with = + +.To calculate a Pythagorean triple, take any term of this sequence and convert it to an improper fraction (for mixed number , the corresponding improper fraction is ).