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  2. What is the relationship between power and energy?

    physics.stackexchange.com/questions/374046

    3. Power is the amount of energy produced (or consumed) for unit of time. For exemple, Sun's reaction produces x x MeV of energy per day. So, it's power is x (24∗60∗60) MeV s x (24 ∗ 60 ∗ 60) M e V s. Power = energy time Power = energy time (more precisely dP = dE dt d P = d E d t) Share. Cite.

  3. How much energy is in a lightning strike? - Physics Stack...

    physics.stackexchange.com/questions/19082/how-much-energy-is-in-a-lightning-strike

    You are confused about units. Watt is a unit of power (energy/time), Watt-hour is a unit of energy. 16TW is an estimate of the continuous average power usage of the world - which is about 140,000 TWh each year. If the lightning has a peak power of 1TW for 30 microseconds, this corresponds to an energy content of about 8000 Watt-hours.

  4. 1 Answer. There are two things. More photons means a brighter beam. power (Energy/sec) is proportional to the number of photons/sec. Photons with shorter wavelengths and higher frequencies have more energy. That is a bluer beam has more power. So P = nhν P = n h ν where n is the number of photons/sec. Share.

  5. Why do we calculate energy by integrate the Signal squared?

    physics.stackexchange.com/questions/93337

    Power is simply energy per unit time. Charges are generators of a continuous symmetry via Noether's theorem and exist whenever there is a conserved current, e.g. the derivatives of the current in any direction sum to zero. P=VI is a statement about the proportionality of current to power.

  6. Energy dissipated across a resistor when charging a capacitor

    physics.stackexchange.com/questions/464663

    I am a beginner in Physics and I am a little confused about RC circuits. I am working on a project in which I am measuring the power loss from a resistor when charging a capacitor in an R-C circui...

  7. What is Pressure Energy? - Physics Stack Exchange

    physics.stackexchange.com/questions/216342

    6. The pressure energy is the energy in/of a fluid due to the applied pressure (force per area). So if you have a static fluid in an enclosed container, the energy of the system is only due to the pressure; if the fluid is moving along a flow, then the energy of the system is the kinetic energy as well as the pressure.

  8. How does energy flow in a circuit? Which is correct?

    physics.stackexchange.com/questions/569273/how-does-energy-flow-in-a-circuit...

    The part of EM theory that describes energy flow is called Poynting’s theorem. It says that energy in the EM fields moves from one place to another in a direction that is perpendicular to both the E field and the B field. For a circuit there is a current which creates a B field which wraps circularly around the wire.

  9. Is force the derivative of energy? - Physics Stack Exchange

    physics.stackexchange.com/questions/161195

    7. In my lecture today my professor briefly mentioned that force is the derivative of energy but I did not really get what he meant by that. I tried to express it mathematically: d dtKE = d dt(1 2mv2) = mvdv dt d d t K E = d d t (1 2 m v 2) = m v d v d t. This looks really close to Newton's second law F = ma F = m a but there is an extra " v v ...

  10. Why is Power = Voltage - Physics Stack Exchange

    physics.stackexchange.com/questions/705310/why-is-power-voltage-times-current

    Apr 24, 2022 at 16:44. 1. "...because V is the amount of energy per coulomb". The potential difference, V, between two points is the work required per unit charge (work per coulomb of charge) to move the charge between the two points. Then the rate of work (power) is the voltage times the amount of coulombs per second (current). – Bob D.

  11. How does one prove that Energy = Voltage x Charge?

    physics.stackexchange.com/questions/73769

    829 6 13 20. Voltage is defined as potential energy per charge: V = E q V = E q. There's nothing to prove. But, I think you are really looking for the gain or loss in potential energy formula: ΔV = ΔE/q Δ V = Δ E / q. you just consider the voltage at point A, and the voltage at point B then subtract them. VA −VB = EA q − EB q V A − V ...