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  2. 6174 - Wikipedia

    en.wikipedia.org/wiki/6174

    The only four-digit numbers for which Kaprekar's routine does not reach 6174 are repdigits such as 1111, which give the result 0000 after a single iteration. All other four-digit numbers eventually reach 6174 if leading zeros are used to keep the number of digits at 4.

  3. Kaprekar's routine - Wikipedia

    en.wikipedia.org/wiki/Kaprekar's_routine

    Although 11-digit and 13-digit numbers have only one solution, it forms a loop of five numbers and a loop of two numbers, respectively. [13] Hence, Prichett's result that the Kaprekar's constants are limited to 495 (3 digits) and 6174 (4 digits) [14] is verified.

  4. Quaternary numeral system - Wikipedia

    en.wikipedia.org/wiki/Quaternary_numeral_system

    230210 4 = 10 11 00 10 01 00 2. Since sixteen is a power of four, conversion between these bases can be implemented by matching each hexadecimal digit with two quaternary digits. In the above example, 23 02 10 4 = B24 16

  5. 4-Digits - Wikipedia

    en.wikipedia.org/wiki/4-Digits

    Singapore Pools is the sole provider of gambling games in Singapore. 4-D and lottery 6/49 are two of the most popular. A similar 4-D game with its prize structure fully revealed can be found in Taiwan and Cambodia. [1] [2] 4-Digits is somewhat similar to "Pick 4" in the United States, Canada 5-Digits "Pick 5", and Jackpot in Germany and Malaysia.

  6. Four fours - Wikipedia

    en.wikipedia.org/wiki/Four_fours

    For example, when d=4, the hash table for two occurrences of d would contain the key-value pair 8 and 4+4, and the one for three occurrences, the key-value pair 2 and (4+4)/4 (strings shown in bold). The task is then reduced to recursively computing these hash tables for increasing n , starting from n=1 and continuing up to e.g. n=4.

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    The search engine that helps you find exactly what you're looking for. Find the most relevant information, video, images, and answers from all across the Web.

  8. Divisibility rule - Wikipedia

    en.wikipedia.org/wiki/Divisibility_rule

    Add 4 times the last digit to the rest. The result must be divisible by 13. (Works because 39 is divisible by 13). 637: 63 + 7 × 4 = 91, 9 + 1 × 4 = 13. Subtract the last two digits from four times the rest. The result must be divisible by 13. 923: 9 × 4 − 23 = 13. Subtract 9 times the last digit from the rest. The result must be divisible ...

  9. Significant figures - Wikipedia

    en.wikipedia.org/wiki/Significant_figures

    Then, round the final result, for example, to the fewest number of significant figures (for multiplication or division) or leftmost last significant digit position (for addition or subtraction) among the inputs in the final calculation. [14] (2.3494 + 1.345) × 1.2 = 3.69 4 4 × 1.2 = 4. 4 3328 ≈ 4.4.