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The Greek foot (πούς, pous) had a length of 1 / 600 of a stadion, [12] one stadion being about 181.2 m (594 ft); [13] therefore a foot was, at the time, about 302 mm (11.9 in). Its exact size varied from city to city and could range between 270 mm (10.6 in) and 350 mm (13.8 in), but lengths used for temple construction appear to ...
A fire hydrant marked as 3-inch. The inch (symbol: in or ″) is a unit of length in the British Imperial and the United States customary systems of measurement.It is equal to 1 / 36 yard or 1 / 12 of a foot.
For measuring length, the U.S. customary system uses the inch, foot, yard, and mile, which are the only four customary length measurements in everyday use.From 1893, the foot was legally defined as exactly 1200 ⁄ 3937 m (approximately 0.304 8006 m). [13]
In the evolutionary approach, the foot was to be derived from these lengths by a simple integer factor, which would be either three (pendulum) or five (rod), i.e. lengthening it from the traditional value of about 324 mm by slightly over 1 inch to ca. 331 mm or shortening it by about a quarter of an inch to ca. 298 mm.
The informal public imperial measurement standards erected at the Royal Observatory, Greenwich, London, in the 19th century: 1 British yard, 2 feet, 1 foot, 6 inches, and 3 inches. The inexact monument was designed to permit rods of the correct measure to fit snugly into its pins at an ambient temperature of 62 °F (16.66 °C).
The Compositio redefined the yard, foot, inch, and barleycorn to 10 ⁄ 11 of their previous value. [dubious – discuss] However, it retained the Anglo-Saxon rod of 15 x 11 ⁄ 10 feet (5.03 metres) and the acre of 4 × 40 square rods. Thus, the rod went from 5 old yards to 5 + 1 ⁄ 2 new yards, or 15 old feet to 16 + 1 ⁄ 2 new feet. The ...
≡ 1 ft/(h⋅s) = 8.4 6 × 10 −5 m/s 2: foot per minute per second: fpm/s ≡ 1 ft/(min⋅s) = 5.08 × 10 −3 m/s 2: foot per second squared: fps 2: ≡ 1 ft/s 2 = 3.048 × 10 −1 m/s 2: gal; galileo: Gal ≡ 1 cm/s 2 = 10 −2 m/s 2: inch per minute per second: ipm/s ≡ 1 in/(min⋅s) = 4.2 3 × 10 −4 m/s 2: inch per second squared ...
Similarly, an inch-pound (or pound-inch) is the torque of one pound of force applied to one inch of distance from the pivot, and is equal to 1 ⁄ 12 lbf⋅ft (0.1129848 N⋅m). It is commonly used on torque wrenches and torque screwdrivers for setting specific fastener tension.