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The 1988 United States presidential election in California took place on November 8, 1988, and was part of the 1988 United States presidential election. Voters chose 47 representatives, or electors to the Electoral College , who voted for president and vice president .
Since being admitted to the Union in 1850, California has participated in 43 presidential elections. A bellwether from 1888 to 1996, voting for the losing candidates only three times in that span, California has become a reliable state for Democratic presidential candidates since 1992.
Sullivan County, New York, in 2000 and 2020; Traverse County, Minnesota, in 1988 and 2020; Tuscarawas County, Ohio, in 2012 and 2020; Union County, Iowa, in 1988 and 2020; Val Verde County, Texas, in 2016 and 2020 [3] Vanderburgh County, Indiana, in 2012 and 2020; Ventura County, California, in 2016 and 2024; Warren County, New York, in 1992 ...
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President Trump can cite 1988 as proof that summer polling doesn't always hold up when presidential election ballots are tallied in November. That year, the Republican nominee, George H.W. Bush ...
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California is considered a safe blue state in presidential elections due to large concentrations of Democratic voters in urban regions such as the San Francisco Bay Area, Sacramento, Los Angeles, and San Diego. As predicted, Biden easily carried California on election day, earning 63.5% of the vote and a margin of 29.2% over Trump.
This file has been created using a standardized map of a state's counties: California county map, cb 500k.svg. A full list of available maps exists at Category:Standardized SVG county maps of US states.