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Let's say I have a profit margin of 70% and expenses of $250 can I not calculate my estimated revenue? I'm using this formula: Profit Margin = (Revenue - Expenses) / Revenue. I'm trying to understand what my projected revenue would be given my profit margin and estimated cost. I'm looking for an answer in the form of a formula for Revenue like ...
I need help on this question. Thanks in advance! my calculation is like this: Percentage difference: 31-27=4 4% = £50,000 100% = £1.25mil Need to find total revenue: Profit = Revenue - Cost Not ...
2) Find the level of production that will maximize revenue. 3)Suppose there is a fi xed cost of $174500, to set up the manufacture and a producing cost of 125 dollars per unit. Find the break even quantities.
Calculate the amount of tax revenue collected by the government and the distribution of tax payments between buyers and sellers. Now so far i could do the following . since in equilibrium qty demanded equals qty. supplied. So from the demand and supply functions we get, 0.5Q=200-0.5Q Q=200 . So P=0.5*200= 100
In january, one half of the revenue was generated by video X, since half of the total watch time was spent looking at video X. This means that video X earned 100, half of the total amount. In february, the video earned one quarter of the total amount, meaning it earned 125, making a total of 225.
Say we want to find the tax burden of the consumer, the tax burden of the firm, and the total revenue generated for the government for some excise tax t. Do we do this by looking at the elasticity of each the supplier and consumer? The Elasticity of Q with respect to P can be calculated by: $\eta_Q,_P = P/Q*dQ/dP$
really this is just differentiation, so no need to get too confused here. many relations encountered in science can be expressed in the form: $$ y = f(x) \tag{1} $$ however a more symmetrical expression is sometimes more appropriate; $$ g(x,y) = 0 \tag{2} $$ it is trivial (though un-necessary) to rewrite a relation in form 1 as a relation of the second type, viz: $$ h(x,y) = f(x)-y = 0 ...
You probably want to Maximise your total Revenue so set the Marginal Revenue to 0. A Quantity greater than 50 would actually make you lose Revenue. The Second derivative is negative so you see that anything greater than 50 would make the First derivative less than 0 and the First derivative is the Marginal Change in Total Revenue.
In a small snack shop the average revenue was $\$400$ a day over a $10$ day period. During this period, if the average daily revenue was $\$360$ for the first 6 days, what was the average daily revenue for the last 4 days? Ans=$\$460$
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