enow.com Web Search

Search results

  1. Results from the WOW.Com Content Network
  2. List of gravitationally rounded objects of the Solar System

    en.wikipedia.org/wiki/List_of_gravitationally...

    Pallas (radius 255.5 ± 2 km), the third-largest asteroid, appears never to have completed differentiation and likewise has an irregular shape. Vesta and Pallas are nonetheless sometimes considered small terrestrial planets anyway by sources preferring a geophysical definition, because they do share similarities to the rocky planets of the ...

  3. Gravity of Mars - Wikipedia

    en.wikipedia.org/wiki/Gravity_of_Mars

    Finding k 2 is helpful in understanding the interior structure on Mars. [13] The most updated k 2 obtained by Genova's team is 0.1697 ± 0.0009. [13] As if k 2 is smaller than 0.10 a solid core would be indicated, this tells that at least the outer core is liquid on Mars, [31] and the predicted core radius is 1520–1840 km. [31]

  4. Surface gravity - Wikipedia

    en.wikipedia.org/wiki/Surface_gravity

    If its mass is no more than 5 times that of the Earth, as is expected, [6] and if it is a rocky planet with a large iron core, it should have a radius approximately 50% larger than that of Earth. [7] [8] Gravity on such a planet's surface would be approximately 2.2 times as strong as on Earth. If it is an icy or watery planet, its radius might ...

  5. List of Solar System objects by size - Wikipedia

    en.wikipedia.org/wiki/List_of_Solar_System...

    For example, if a TNO is incorrectly assumed to have a mass of 3.59 × 10 20 kg based on a radius of 350 km with a density of 2 g/cm 3 but is later discovered to have a radius of only 175 km with a density of 0.5 g/cm 3, its true mass would be only 1.12 × 10 19 kg.

  6. Equations for a falling body - Wikipedia

    en.wikipedia.org/wiki/Equations_for_a_falling_body

    The first equation shows that, after one second, an object will have fallen a distance of 1/2 × 9.8 × 1 2 = 4.9 m. After two seconds it will have fallen 1/2 × 9.8 × 2 2 = 19.6 m; and so on. On the other hand, the penultimate equation becomes grossly inaccurate at great distances.

  7. Standard gravitational parameter - Wikipedia

    en.wikipedia.org/wiki/Standard_gravitational...

    μ = Gm 1 + Gm 2 = μ 1 + μ 2, where m 1 and m 2 are the masses of the two bodies. Then: for circular orbits, rv 2 = r 3 ω 2 = 4π 2 r 3 /T 2 = μ; for elliptic orbits, 4π 2 a 3 /T 2 = μ (with a expressed in AU; T in years and M the total mass relative to that of the Sun, we get a 3 /T 2 = M) for parabolic trajectories, rv 2 is constant and ...

  8. Two-body problem in general relativity - Wikipedia

    en.wikipedia.org/wiki/Two-body_problem_in...

    A line joining a planet and the Sun sweeps out equal areas during equal intervals of time. The square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit. Kepler published the first two laws in 1609 and the third law in 1619.

  9. Mars - Wikipedia

    en.wikipedia.org/wiki/Mars

    At the bottom of the mantle lies a basal liquid silicate layer approximately 150–180 km thick. [44] [54] Mars's iron and nickel core is completely molten, with no solid inner core. [55] [56] It is around half of Mars's radius, approximately 1650–1675 km, and is enriched in light elements such as sulfur, oxygen, carbon, and hydrogen. [57] [58]