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The table below lists various gauge sizes with weights. The bores marked * are found in punt guns, obsolete, or rare weapons only. However, 4 gauge was sometimes found used in blunderbuss guns made for coach defense and protection against piracy. The .410 and 23 mm are exceptions; they are actual bore sizes, not gauges. If the .410 bore and 23 ...
BL 4 inch Mk VII 50-caliber United Kingdom: World War I - World War II 102 mm (4.0 in) BL 4 inch Mk VIII & XI 40-caliber United Kingdom: World War I - World War II 102 mm (4.0 in) BL 4 inch Mk IX naval gun 45-caliber United Kingdom: World War I - World War II 102 mm (4.0 in) QF 4 inch Mk I - III 40-caliber United Kingdom: 1895 - World War I
All 20 mm cartridges have an outside projectile diameter and barrel bore diameter of approximately 0.787 inches (20.0 mm). These projectiles are typically 75 to 127 mm (3–5 in) long, cartridge cases are typically 75 to 152 mm (3–6 in) long, and most are shells , with an explosive payload and detonating fuze .
The VPAM scale as of 2009 runs from 1 to 14, with 1-5 being soft armor, and 6-14 being hard armor. [1] Tested armor must withstand three hits, spaced 120 mm (4.7 inches) apart, of the designated test threat with no more than 25 mm (0.98 inches) of back-face deformation in order to pass.
Nominal Pipe Size (NPS) is a North American set of standard sizes for pipes used for high or low pressures and temperatures. [1] " Nominal" refers to pipe in non-specific terms and identifies the diameter of the hole with a non-dimensional number (for example – 2-inch nominal steel pipe" consists of many varieties of steel pipe with the only criterion being a 2.375-inch (60.3 mm) outside ...
The major minus pitch also works for inch-based threads, but you must first determine the pitch by looking at the number of treads per inch (TPI; for example, 1 ⁄ 20 = 0.050 and 1 ⁄ 13 ≈ 0.077), and your result will only land near a tap drill size (not directly on one). Example (inch coarse): For 7 ⁄ 16-14, 1 in ÷ 14 = 0.071 in; 0.437 ...
The cross-sectional area of a bar, as given by πr², works out to (bar size/9.027)², which is approximated as (bar size/9)² square inches. For example, the area of #8 bar is (8/9)² = 0.79 square inches. Bar sizes larger than #8 follow the 1 ⁄ 8-inch rule
If using the metric unit meters for distance and the imperial unit inches for target size, one has to multiply by a factor of 25.4, since one inch is defined as 25.4 millimeters. distance in meters = target in inches angle in mrad × 25.4 {\displaystyle {\text{distance in meters}}={\frac {\text{target in inches}}{\text{angle in mrad}}}\times 25.4}