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Heat capacity, c p [2] 96 J/(mol K) Liquid properties Std enthalpy change of formation, Δ f H o liquid: −249.4 kJ/mol Standard molar entropy, S o liquid: 200.4 J/(mol K) Enthalpy of combustion, Δ c H o –1785.7 kJ/mol Heat capacity, c p: 125.5 J/(mol K) Gas properties Std enthalpy change of formation, Δ f H o gas: −218.5 kJ/mol Standard ...
The analysis here shows the simple unattributed formula and the Antoine equation are reasonably accurate at 100 °C, but quite poor for lower temperatures above freezing. Tetens is much more accurate over the range from 0 to 50 °C and very competitive at 75 °C, but Antoine's is superior at 75 °C and above.
6.7 kJ/mol at –87.0 °C crystal II → crystal I Entropy of transition, Δ trs S o: 36 J/(mol·K) at –87.0 °C crystal II → crystal I Liquid properties Std enthalpy change of formation, Δ f H o liquid –156.4 kJ/mol Standard molar entropy, S o liquid: 204 J/(mol K) Enthalpy of combustion, Δ c H o –3919.6 kJ/mol Heat capacity, c p
This is a list of cities by average temperature (monthly and yearly). The temperatures listed are averages of the daily highs and lows. Thus, the actual daytime temperature in a given month may be considerably higher than the temperature listed here, depending on how large the difference between daily highs and lows is.
T c is the temperature at the critical point, and; P c is the pressure at the critical point. The Redlich–Kwong equation can also be represented as an equation for the compressibility factor of gas, as a function of temperature and pressure: [8]
Normal boiling points for pure substances, bubble and dew points for zeotropic blends, or normal boiling point and azeotropic temperature for the azeotropic blends, at 101,325 Pa (1 atmosphere) and in degrees Celsius
This allows one to easily determine inverses of many functions that are given by algebraic formulas. For example, if f is the function = (+) then to determine () for a real number y, one must find the unique real number x such that (2x + 8) 3 = y. This equation can be solved:
The simplest of the cyclopentadienyls are Th(C 5 H 5) 3 and Th(C 5 H 5) 4: many derivatives are known. The former (which has two forms, one purple and one green) [ 71 ] is a rare example of thorium in the formal +3 oxidation state; [ 72 ] a formal +2 oxidation state occurs in a derivative. [ 73 ]