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The two basic types are the arithmetic left shift and the arithmetic right shift. For binary numbers it is a bitwise operation that shifts all of the bits of its operand; every bit in the operand is simply moved a given number of bit positions, and the vacant bit-positions are filled in.
P = 0000 1100 0. The last two bits are 00. P = 0000 0110 0. Arithmetic right shift. P = 0000 0110 0. The last two bits are 00. P = 0000 0011 0. Arithmetic right shift. P = 0000 0011 0. The last two bits are 10. P = 1101 0011 0. P = P + S. P = 1110 1001 1. Arithmetic right shift. P = 1110 1001 1. The last two bits are 11. P = 1111 0100 1 ...
Shifting right by n bits on an unsigned binary number has the effect of dividing it by 2 n (rounding towards 0). Logical right shift differs from arithmetic right shift. Thus, many languages have different operators for them. For example, in Java and JavaScript, the logical right shift operator is >>>, but the arithmetic right shift operator is >>.
Verilog was created by Prabhu Goel, Phil Moorby and Chi-Lai Huang between late 1983 and early 1984. [3] Chi-Lai Huang had earlier worked on a hardware description LALSD, a language developed by Professor S.Y.H. Su, for his PhD work. [4]
Left arithmetic shift Right arithmetic shift. In an arithmetic shift, the bits that are shifted out of either end are discarded. In a left arithmetic shift, zeros are shifted in on the right; in a right arithmetic shift, the sign bit (the MSB in two's complement) is shifted in on the left, thus preserving the sign of the operand.
In all single-bit shift operations, the bit shifted out of the operand appears on carry-out; the value of the bit shifted into the operand depends on the type of shift. Arithmetic shift: the operand is treated as a two's complement integer, meaning that the most significant bit is a "sign" bit and is preserved.
The very fastest shifters are implemented as full crossbars, in a manner similar to the 4-bit shifter depicted above, only larger. These incur the least delay, with the output always a single gate delay behind the input to be shifted (after allowing the small time needed for the shift count decoder to settle; this penalty, however, is only incurred when the shift count changes).
In binary encoding each long number is multiplied by one digit (either 0 or 1), and that is much easier than in decimal, as the product by 0 or 1 is just 0 or the same number. Therefore, the multiplication of two binary numbers comes down to calculating partial products (which are 0 or the first number), shifting them left, and then adding them ...