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Similarly a number of the form 10x + y is divisible by 7 if and only if x + 5y is divisible by 7. [8] So add five times the last digit to the number formed by the remaining digits, and continue to do this until a number is obtained for which it is known whether it is divisible by 7. [9] Another method is multiplication by 3.
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An integer is even if it is divisible by 2, and odd if it is not. [1] For example, −4, 0, and 82 are even numbers, while −3, 5, 7, and 21 are odd numbers. The above definition of parity applies only to integer numbers, hence it cannot be applied to numbers like 1/2 or 4.201.
It is divisible by 2 and by 7. 224: it is divisible by 2 and by 7. Add the last two digits to twice the rest. The answer must be divisible by 7. 364: (3 × 2) + 64 = 70." Well, I think there is a mistake. Obviously 371 is not divisible by 14 but (3×2)+71=77. Where it is written "The answer must be divisible by 7" it should be written "The ...
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Two properties of 1001 are the basis of a divisibility test for 7, 11 and 13. The method is along the same lines as the divisibility rule for 11 using the property 10 ≡ -1 (mod 11). The two properties of 1001 are 1001 = 7 × 11 × 13 in prime factors 10 3 ≡ -1 (mod 1001) The method simultaneously tests for divisibility by any of the factors ...
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