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The "acceleration of gravity" (involved in the "force of gravity") never contributes to proper acceleration in any circumstances, and thus the proper acceleration felt by observers standing on the ground is due to the mechanical force from the ground, not due to the "force" or "acceleration" of gravity. If the ground is removed and the observer ...
Even if we pick units where =, the magnitude of the proper acceleration will depend on our choice of units: for example, if we use units of light-years for distance, (or ) and years for time, (or ), this would mean = light year/year 2, equal to about 9.5 meters/second 2, while if we use units of light-seconds for distance, (or ), and seconds ...
Proper acceleration, the acceleration of a body relative to a free-fall condition, is measured by an instrument called an accelerometer. In classical mechanics, ...
Thus the magnitude of four-acceleration corresponds to the magnitude of proper acceleration. By combining this with ( 2b ), an alternative method for the determination of the connection between a 0 {\displaystyle \mathbf {a} ^{0}} in S ′ {\displaystyle S'} and a {\displaystyle \mathbf {a} } in S {\displaystyle S} is given, namely [ 13 ] [ 17 ]
An accelerometer measures proper acceleration, which is the acceleration it experiences relative to freefall and is the acceleration felt by people and objects. [2] Put another way, at any point in spacetime the equivalence principle guarantees the existence of a local inertial frame, and an accelerometer measures the acceleration relative to that frame. [4]
So, calculations made in both frames show that the thread will break; in S′ due to the non-simultaneous acceleration and the increasing distance between the spaceships, and in S due to length contraction of the thread. In the following, the rest length [3] or proper length [4] of an object
For free bodies, the specific force is the cause of, and a measure of, the body's proper acceleration. The acceleration of an object free falling towards the earth depends on the reference frame (it disappears in the free-fall frame, also called the inertial frame), but any g-force "acceleration" will be present in all frames.
The proper distance to the horizon is finite, [20] so the length of rope needed would be finite as well, but if the rope were lowered slowly (so that each point on the rope was approximately at rest in Schwarzschild coordinates), the proper acceleration experienced by points on the rope closer and closer to the horizon would approach infinity ...