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The probability of any two people not having the same birthday is 364 / 365 . In a room containing n people, there are (n 2) = n(n − 1) / 2 pairs of people, i.e. (n 2) events. The probability of no two people sharing the same birthday can be approximated by assuming that these events are independent and hence by multiplying ...
After the problem appeared in Parade, approximately 10,000 readers, including nearly 1,000 with PhDs, wrote to the magazine, most of them calling Savant wrong. [4] Even when given explanations, simulations, and formal mathematical proofs, many people still did not accept that switching is the best strategy. [5]
The Boy or Girl paradox surrounds a set of questions in probability theory, which are also known as The Two Child Problem, [1] Mr. Smith's Children [2] and the Mrs. Smith Problem. The initial formulation of the question dates back to at least 1959, when Martin Gardner featured it in his October 1959 " Mathematical Games column " in Scientific ...
Goldbach’s Conjecture. One of the greatest unsolved mysteries in math is also very easy to write. Goldbach’s Conjecture is, “Every even number (greater than two) is the sum of two primes ...
They’re arranged in groups of two-digit numbers; you add eight to the top two-digit number (75, 34, 68) to get the bottom number (83, 42, 76). Keeping score Math puzzle
In this case the problem reduces to n − 2 people and n − 2 hats, because P 1 received h i ' s hat and P i received h 1 's hat, effectively putting both out of further consideration. For each of the n − 1 hats that P 1 may receive, the number of ways that P 2, ..., P n may all receive hats is the sum of the counts for the two cases.
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