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The post-increment and post-decrement operators increase (or decrease) the value of their operand by 1, but the value of the expression is the operand's value prior to the increment (or decrement) operation. In languages where increment/decrement is not an expression (e.g., Go), only one version is needed (in the case of Go, post operators only).
Augmented assignment (or compound assignment) is the name given to certain assignment operators in certain programming languages (especially those derived from C).An augmented assignment is generally used to replace a statement where an operator takes a variable as one of its arguments and then assigns the result back to the same variable.
The binary logical operators returned a Boolean value in early versions of JavaScript, but now they return one of the operands instead. The left–operand is returned, if it can be evaluated as : false , in the case of conjunction : ( a && b ), or true , in the case of disjunction : ( a || b ); otherwise the right–operand is returned.
Depending on the language, an explicit assignment sign may be used in place of the equal sign (and some languages require the word int even in the numerical case). An optional step-value (an increment or decrement ≠ 1) may also be included, although the exact syntaxes used for this differ a bit more between the languages.
The semantics of operators particularly depends on value, evaluation strategy, and argument passing mode (such as Boolean short-circuiting). Simply, an expression involving an operator is evaluated in some way, and the resulting value may be just a value (an r-value), or may be an object allowing assignment (an l-value).
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Operator symbol. Ruby: as last object of line; comment may follow operator; AutoHotkey: As the first character of continued line; any expression operators except ++ and --, and a comma or a period [7] Some form of line comment serves as line continuation. Turbo Assembler: \ m4: dnl; TeX: % Character position
The article states that the "increment operator increases the value of its operand by 1", but this is only sometimes correct, and misses the point of the operator. The operator actually increases the value by an amount that reflects the number of machine words required to store the data.