Search results
Results from the WOW.Com Content Network
gcd(m, n) (greatest common divisor of m and n) is the product of all prime factors which are both in m and n (with the smallest multiplicity for m and n). m and n are coprime (also called relatively prime) if gcd(m, n) = 1 (meaning they have no common prime factor).
The elements 2 and 1 + √ −3 are two maximal common divisors (that is, any common divisor which is a multiple of 2 is associated to 2, the same holds for 1 + √ −3, but they are not associated, so there is no greatest common divisor of a and b.
Synonyms for GCD include greatest common factor (GCF), highest common factor (HCF), highest common divisor (HCD), and greatest common measure (GCM). The greatest common divisor is often written as gcd( a , b ) or, more simply, as ( a , b ) , [ 3 ] although the latter notation is ambiguous, also used for concepts such as an ideal in the ring of ...
Set square shaped as 45° - 45° - 90° triangle The side lengths of a 45° - 45° - 90° triangle 45° - 45° - 90° right triangle of hypotenuse length 1.. In plane geometry, dividing a square along its diagonal results in two isosceles right triangles, each with one right angle (90°, π / 2 radians) and two other congruent angles each measuring half of a right angle (45°, or ...
≡ 1 ft 3 /min = 4.719 474 432 × 10 −4 m 3 /s: cubic foot per second ft 3 /s ≡ 1 ft 3 /s = 0.028 316 846 592 m 3 /s: cubic inch per minute in 3 /min ≡ 1 in 3 /min = 2.731 177 3 × 10 −7 m 3 /s cubic inch per second in 3 /s ≡ 1 in 3 /s = 1.638 7064 × 10 −5 m 3 /s: cubic metre per second (SI unit) m 3 /s ≡ 1 m 3 /s = 1 m 3 /s ...
In an equilateral triangle, the 3 angles are equal and sum to 180°, therefore each corner angle is 60°. Bisecting one corner, the special right triangle with angles 30-60-90 is obtained. By symmetry, the bisected side is half of the side of the equilateral triangle, so one concludes sin ( 30 ∘ ) = 1 / 2 {\displaystyle \sin(30^{\circ ...
A primitive Pythagorean triple is one in which a, b and c are coprime (that is, they have no common divisor larger than 1). [1] For example, (3, 4, 5) is a primitive Pythagorean triple whereas (6, 8, 10) is not. Every Pythagorean triple can be scaled to a unique primitive Pythagorean triple by dividing (a, b, c) by their greatest common divisor ...
As (a, b) and (b, rem(a,b)) have the same divisors, the set of the common divisors is not changed by Euclid's algorithm and thus all pairs (r i, r i+1) have the same set of common divisors. The common divisors of a and b are thus the common divisors of r k−1 and 0. Thus r k−1 is a GCD of a and b. This not only proves that Euclid's algorithm ...