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The odds you mentioned are for being born on the same day at the same time. Assuming a precision of 1 minute, this will be $\frac{1}{24\times 365 \times 60} \approx \frac{1}{500000}$ like the article mentions. Without any further data, the best guess towards your question is $\frac{1}{365}$
I know how to get the answer which is 19/49 when considering all 3 people not being born on the same day. However, when I try to calculate the answer directly I seem to get it wrong. Considering exactly 2 people being born on the same day I get 1*1/7*6/7. And then, exactly 3 people is 1*1/7*1/7. Thus, the total is 6/49 + 1/49 = 7/49.
Here's my best guess. There is (roughly) a 1 1 in 30 30 chance that a person is born on the 13 13 th day of any given month. There is a 1 1 in 7 7 chance that a person's 13 13 th birthday occurs on a Friday. Multiplying these two probabilities (7 × 30) (7 × 30) yields roughly a 1 1 in 210 210 chance that a person's 13 13 th birthday occurrs ...
What is the probability that in a class of $25$ students at least three are born in the same month? 1 Probability that in a group of 25 people there are at least 10 unique birth months
The probability of getting at least one success is obtained from the Poisson distribution: P( at least one triple birthday with 30 people) ≈ 1 − exp(−(30 3)/3652) =.0300. P ( at least one triple birthday with 30 people) ≈ 1 − exp (− (30 3) / 365 2) =.0300. You can modify this formula for other values, changing either 30 or 3.
What is the probability two people (individuals) will have the same exact birthday? There are 365 days in a year and I assume that any person can be born on any random day, so uniformly. I like ...
According to birth statistics; the number of babies born alive in 2020 was 1 million 112 thousand 859. 570 thousand 892 of them were boys, and 541 thousand 967 of them were girls. 97.1% of the babies born alive were single births, 2.9% were twins, and 0.1% were triplets or more.
Probability that there are at least 2 people in the room born on the same day = 1 - (No one was born on the same day) - (Exactly one person was born on the same day) There are (3 choose 2) different pairs of couples. Each couple has the same birthday as another couple with the chances of 1/7 and different with chances 6/7. Thus:
Calculate the probability that the five people are born on five different days, and subtract from $1$. First, choose the five different days $(_7C_5)$ and then pick what order the five people are born in $(5!).$ This gives $21\cdot 120 = 2520$ possibilities. There are $7^5 = 16807$ total possibilities. So the answer is
There is some hype now about a Polish village where the last 12 children born were all girls. The probability that the last 12 newborns in a village are all girls is around 0.03%, so around 3000 villages give us a solid 50% chance of this happening, so I would say this is no big deal.