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Hope it helps... Rotational speed omega can be evaluated considering the change in angular displacement theta with time t. omega=theta/t Practically this can be a bit dfficult so what we do to measure the rotational speed of, say, a motor shaft is to visually count the number of rotations per minute. We observe a point on the rim of the rotating shaft and we count the number of rotations (say ...
For a freely rotating rigid body omega\prop1/m For a freely rotating rigid body having mass m, radius of gyration k & an angular velocity omega, net torque T_{\text{net}} on the body must be zero T_{\text{net}}=0 I(\frac{d\omega}{dt})=0 \frac{d(I\omega)}{dt}=0 I\omega=\text{const} mk^2\omega=\text{const} \omega=\frac{\text{const}}{mk^2} omega\prop1/m thus when the mass m of a freely rotating ...
The earth rotates at 465 meters/second or 1040 miles/hour. This can be calculated by dividing the length of a day, which is just under 24 hours, into the distance a point on the equator travel in that time. This value is the circumference of the earth, or 40075 km. 40075/23.93=465 The earth rotate at 465 m/s.
The study of dynamics falls under two categories: linear and rotational. Rotational dynamics pertains to objects that are rotating or moving in a curved path. In the dynamics of rotational motion, unlike the linear case, we do not have Newton's Laws to guide us. Instead, we develop parallel concepts to those of linear dynamics. Rotational dynamics involves quantities such as torque, rotational ...
torque is a twisting force that causes an object to rotate. Rotation is the speed at which an object spins around its axis. torque is a function of both anguar acceleration (alpha) and rotational inertia ("I") --> torque = "I" (alpha) "I" is a measure of an objects resistance to rotation. Big "I" means an object rotates slowly; small "I" means an object rotates faster. "I" = mr^2 --> therefore ...
The rotational speed will vary depending on the radius of the object imparting the artificial gravitational field. From the physics laws governing rotational and orbital motion, the centripetal Force =mw^2r. If we want the same gravitational acceleration as on planet Earth then the rotational speed w=sqrt (a_R/r) Where w - radians /s a_R = 9.8 m/s^2 r - radius of the rotating object in metres ...
The Coriolis Effect would double if the angular speed (the speed of rotation) of the Earth were to double. Since the strength of the Coriolis Force (really a fictitious force, but we won't get into that here) is directly proporotional to both the speed of the object, such as an air mass relative to the Earth and to the rotational speed of the Earth, if the latter was to be doubled, the force ...
Earth rotates itself in 23 hours 54 minutes and 4 seconds once. Moon rotates itself in 27 days 8 hours once.It also revolves around Earth in the same period. Now calculate the circumference of earth and moon .from orbital time you can calculated the speed of each..
v=omegaR Linear velocity v is equal to the angular speed omega times the radius from the center of motion R. We can derive this relationship from the arclength equation S=thetaR where theta is measured in radians. Start with S=thetaR Take a derivative with respect to time on both sides d S/"dt"=d theta/"dt"R d S/"dt" is linear velocity and d theta/"dt" is angular velocity So we're left with: v ...
A simple pendulum consists of a bob of mass m suspended from a friction-less and fixed pivot with the help of a mass-less, rigid, inextensible rod of length L. Its position with respect to time t can be described by the angle theta (measured against a reference line, usually vertical line). As shown in the figure above the driving force is F=-mgsintheta where the -ve sign implies that the ...