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Again, dates in Oracle don't have a format until they are displayed in 'string' format. This is controlled by the parameter NLS_DATE_FORMAT. >>your solution gives me I'm guessing that is incorrect? If the data types are dates, my query should return pretty close to the other. I say pretty close because the to_date on a date strips the time ...
Need help formulaing SQL statement for calculating number of day between two dates. Using php to access MySQL database. The columns are 'id', 'date_in', and 'date_out'. I'm using the MySQL date format (YYYY-MM-DD). Example... date_in = 2008-04-20 date_out=2008-04-22 The result would be 3.
Hi, I have two dates which I need to find the difference between, but I need the difference in days which excludes Saturdays and Sundays. So if the startdate was a thursday and the enddate would be a monday, I would require a count for thursday, friday and monday. Can anyone help please. Thanks
I know, but using this you get the real difference between two dates, like the days between the two dates (Double). In the TimeSpan, there is no Month property. And in my case, the method is using one month as 100%, so every month can have different amount of days.
I need to count the number of WORKING days between two dates in a calculated column in SharePoint 2007. Does anyone know of a formula to do this? I know that "=DATEDIF(Column1, Column2,"d")" provides the total number of days, but the customer wants only the number of WORKING days, i.e. M-F. Excel has a formula for it...can't seem to find one ...
DELIMITER $$ DROP FUNCTION IF EXISTS `xxx`.`get_weekday` $$ CREATE FUNCTION `xxx`.`get_weekday` (first_date date, last_date date, curr_week_day int) RETURNS INT BEGIN DECLARE days_tot int; DECLARE whole_weeks int; DECLARE first_day int; DECLARE last_day int; SET whole_weeks = FLOOR(DATEDIFF(last_date,first_date)/7) ; SET first_day = WEEKDAY ...
Example: two weeks difference is 14; divide by 7, and multiply that result by 5: Answer is 10. Go to 16 days; divided by 7 is 2.85; times 5 results in 11.42, or 12 rounded up. 18 days (two weeks, three days) results in 13. Like I said, it's simple -- perhaps someone else will jump in and provide the accurate function. HTH a little.
I want to recive data who count days per month between to dates. The table have following fields that must be used: BID(INT) - The ID RegNr(Varchar) - The registration number of the car.
With this query, I can generate a list of 100 consecutive days: SELECT DateAdd("d", lng_Number, [StartDate]) as MyDate FROM qry_Numbers WHERE DateAdd("d", lng_Number, [StartDate]) < [EndDate] Using this as a subquery, you can include your table and generate the count of records per day.
// Get difference between dates in milliseconds var milliseconds = MaturityDate.getTime() - SettlementDate.getTime(); // Define number of milliseconds in one day var nMilliSecondsPerDay = 24 * 60 * 60 * 1000; // Get difference in days var days = Math.floor(milliseconds / nMilliSecondsPerDay); Select all Open in new window