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  2. Seasonal energy efficiency ratio - Wikipedia

    en.wikipedia.org/wiki/Seasonal_energy_efficiency...

    On the customer bill, the electric utility states the amount of electric energy, in kilowatt-hours (kW·h), that the customer used since the last bill, and the cost of the energy per kilowatt-hour (kW·h). Air-conditioner sizes are often given as "tons" of cooling, where 1 ton of cooling equals 12,000 BTU/h (3.5 kW). 1 ton of cooling equals the ...

  3. Cooling load temperature difference calculation method

    en.wikipedia.org/wiki/Cooling_load_temperature...

    The first of the cooling load factors used in this method is the CLTD, or the Cooling Load Temperature Difference. This factor is used to represent the temperature difference between indoor and outdoor air with the inclusion of the heating effects of solar radiation. [1] [5] The second factor is the CLF, or the cooling load factor.

  4. Heating seasonal performance factor - Wikipedia

    en.wikipedia.org/wiki/Heating_seasonal...

    Example: For a heat pump delivering 120,000,000 BTU during the season, when consuming 15,000 kWh, the HSPF can be calculated as : HSPF = 120000000 (BTU) / (1000) / 15000 (kWh) HSPF = 8. The HSPF is related to the non-dimensional Coefficient of Performance (COP) for a heat pump, which measures the ratio of heat delivered to work done by the ...

  5. Top5 Ways to Cut Air Conditioner Costs - AOL

    www.aol.com/top5/ways-to-cut-ac-costs

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  6. Coefficient of performance - Wikipedia

    en.wikipedia.org/wiki/Coefficient_of_performance

    The coefficient of performance or COP (sometimes CP or CoP) of a heat pump, refrigerator or air conditioning system is a ratio of useful heating or cooling provided to work (energy) required. [ 1 ] [ 2 ] Higher COPs equate to higher efficiency, lower energy (power) consumption and thus lower operating costs.

  7. Heating degree day - Wikipedia

    en.wikipedia.org/wiki/Heating_degree_day

    As total energy consumption is in kilowatt hours and heating degree days are [no. days×degrees] we must convert watts per kelvin into kilowatt hours per degree per day by dividing by 1000 (to convert watts to kilowatts), and multiplying by 24 hours in a day (1 kW = 1 kW⋅h/h).

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