Search results
Results from the WOW.Com Content Network
2,4,6-Tribromoaniline can be prepared by treating bromine water with aniline in a solution of acetic acid or dilute hydrochloric acid: [1] By reacting bromine with aniline in water, a white precipitate immediately forms and that is 2,4,6-tribromoaniline
Brominating aniline with elemental bromine gives 2,4,6-tribromoaniline. This is then diazotized, then reacted with ethanol to replace the diazonium group with hydrogen, forming 1,3,5-tribromobenzene. [3] It has also been prepared by these methods: [3] replacement of the amino group of 3,5-dibromoaniline with bromine
The bromoanilines form a group of three isomers where the bromine atom occupies the para, ortho or meta position on the aromatic ring. Bromoaniline isomers Arene substitution patterns. The three isomers are: 2-Bromoaniline (o-Bromoaniline) [1] 3-Bromoaniline (m-Bromoaniline) [2] 4-Bromoaniline (p-Bromoaniline) [3]
4-Bromoaniline is a compound where an aniline molecule is substituted with a bromine atom on the para position. Commercially available, this compound may be used as a building block, e.g. in the preparation of monobrominated biphenyl via the Gomberg-Bachmann reaction. [2]
Industrially, it is mainly produced by the reaction of hydrogen gas with bromine gas at 200–400 °C with a platinum catalyst. However, reduction of bromine with red phosphorus is a more practical way to produce hydrogen bromide in the laboratory: [2] 2 P + 6 H 2 O + 3 Br 2 → 6 HBr + 2 H 3 PO 3 H 3 PO 3 + H 2 O + Br 2 → 2 HBr + H 3 PO 4
Stanley is recalling 2.6 million mugs sold in the U.S. after the company received dozens of consumer complaints, including some users who reported getting burned and requiring medical attention ...
My heart! At the end when they were sleeping with her, I totally melted! This brought back so many memories for me of bringing home our babies and our Westies meeting them for the first time.
The formation of a brominated phenol (i.e. 2,4,6-tribromophenol) or aniline (i.e. 2,4,6-tribromoaniline) in form of a white precipitate indicates that the unknown was a phenol or aniline. The more unsaturated an unknown is, the more bromine it reacts with, and the less coloured the solution will appear. [1]