Search results
Results from the WOW.Com Content Network
That is, the value of an octal "10" is the same as a decimal "8", an octal "20" is a decimal "16", and so on. In a hexadecimal system, there are 16 digits, 0 through 9 followed, by convention, with A through F. That is, a hexadecimal "10" is the same as a decimal "16" and a hexadecimal "20" is the same as a decimal "32".
Below is a chart providing the decimal-fraction equivalents that are most relevant to fractional-inch drill bit sizes (that is, 0 to 1 by 64ths). (Decimal places for .25, .5, and .75 are shown to thousandths [.250, .500, .750], which is how machinists usually think about them ["two-fifty", "five hundred", "seven-fifty"]. Machinists generally ...
Using all numbers and all letters except I and O; the smallest base where 1 / 2 terminates and all of 1 / 2 to 1 / 18 have periods of 4 or shorter. 35: Covers the ten decimal digits and all letters of the English alphabet, apart from not distinguishing 0 from O. 36: Hexatrigesimal [57] [58]
1 8-bit to 9-bit bus transceiver with parity register, non-inverting three-state 24 SN74ABT833: 74x834 1 8-bit to 9-bit bus transceiver with parity register, inverting three-state 24 IDT74FCT834: 74x835 1 8-bit shift register with 2:1 input multiplexers, one input latched, serial output 24 74F835: 74x839 1 field-programmable logic array 14x32x6
Thus the letter A, which is (12,1) in the punched card format, is encoded (B,A,1). The currency symbol $, (11,8,3) in the punched card, was encoded in memory as (B,8,2,1). This allows the circuitry to convert between the punched card format and the internal storage format to be very simple with only a few special cases.
By using a dot to divide the digits into two groups, one can also write fractions in the positional system. For example, the base 2 numeral 10.11 denotes 1×2 1 + 0×2 0 + 1×2 −1 + 1×2 −2 = 2.75. In general, numbers in the base b system are of the form:
Example: Convert 764 8 to decimal: 764 8 = 7 × 8 2 + 6 × 8 1 + 4 × 8 0 = 448 + 48 + 4 = 500 10. For double-digit octal numbers this method amounts to multiplying the lead digit by 8 and adding the second digit to get the total. Example: 65 8 = 6 × 8 + 5 = 53 10
If an unknown weight W is balanced with 3 (3 1) on its pan and 1 and 27 (3 0 and 3 3) on the other, then its weight in decimal is 25 or 10 1 1 in balanced base-3. 10 1 1 3 = 1 × 3 3 + 0 × 3 2 − 1 × 3 1 + 1 × 3 0 = 25.