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There is an algorithm to calculate the square root quite simple (the Babylonian algorithm). We want to calculate the square root of #81#, we first guess a possible value. For example we know that #10*10=100# and #7*7=49#, then we can imagine that the square root of #81# is between #7# and #10#, we can imagine for example #8.3#.
9 To find the square root of 81, or sqrt81, we have two find one number, that when multiplying itself, equals to 81. That number is 9 -> (9 * 9 = 81) Therefore sqrt81 = 9.
Just simplify the radicals. sqrt25=5 sqrt81=9 sqrt25/sqrt81=5/9
The answer is: x = 9/5 You first move the -81 to the other side of the "equal" sign, it'll become positive instead of negative. 25x^2 = 81 We then get the square root of both sides of the equation. sqrt(25x^2) = sqrt81 The square roots are: 25 = 5 xx 5 x^2 = x xx x 81 = 9 xx 9 Applying this to our equation makes it like this. 5x = 9 We divide both sides by 5 (5x)/5 = 9/5 This cancels both 5 on ...
sqrt(-81) = 9i The imaginary unit i satisfies i^2=-1 So we find: (9i)^2 = 9^2i^2 = 81 * (-1) = -81 So 9i is a square root of -81 Note that: (-9i)^2 = (-9)^2 i^2 = 81*(-1) = -81 So -9i is also a square root of -81 What does sqrt(-81) mean? sqrt(-81) denotes the principal square root of -81, but which is the principal one? By convention and definition, if n < 0 then: sqrt(n) = sqrt(-n)i So we ...
64 From what you are asking, I believe that you are asking about the perfect square between 49 and 81. The square root of 49 is .7.
#sqrt (81/16)# We simplify #81# and #16# by prime factorisation (expressing a number as a product of its prime factors).
#sqrt(-1)xxsqrt(81)# the #sqrt(-1)# is actually the complex number i. Therefore u can transform it to i which leaves u with #isqrt(81)# from there, u simplify the 81 as per normal so ur answer should be #9i#
See below: Let's say we have sqrtn This is irrational if n is a prime number, or has no perfect square factors. When we simplify radicals, we try to factor out perfect squares. For example, if we had sqrt(54) We know that 9 is a perfect square, so we can rewrite this as sqrt9*sqrt6 =>3sqrt6 We know that 6 is the same as 3*2, but neither of those numbers are perfect squares, so we can't ...
3/4=0.75 If you have a multiplication or division inside a square root you can separate them. sqrt(81/144 ...