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That leaves us with 4 sides of each cube (total of 8) for another 8 digits. However, digit 0 needs to be combined with all other digits, so it also needs to be placed on both cubes. That means we need to place remaining 7 digits (from 3 to 9) on the remaining 6 sides of cubes. The solution is possible because digit 6 looks like inverted 9.
You would expect to score 3 of 6 or better once in around 36.19 drawings. Notice that It takes a 3 if 6 wheel of 163 combinations to be sure of at least one 3/6 score. 1/p changes when several distinct combinations are played together. It mostly is about winning something, not just the jackpot.
The following is an example of an abbreviated wheeling system for a pick-6 lottery with 10 numbers, 4 if 4 guarantee, and the minimum possible number of combinations for that guarantee (20). A template for an abbreviated wheeling system is given as 20 combinations on the numbers from 1 to 10.
2 of 5 barcode (non-interleaved) POSTNET barcode. A two-out-of-five code is a constant-weight code that provides exactly ten possible combinations of two bits, and is thus used for representing the decimal digits using five bits. [1] Each bit is assigned a weight, such that the set bits sum to the desired value, with an exception for zero.
The number associated in the combinatorial number system of degree k to a k-combination C is the number of k-combinations strictly less than C in the given ordering. This number can be computed from C = {c k, ..., c 2, c 1} with c k > ... > c 2 > c 1 as follows.
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The list of all single-letter-single-digit combinations contains ... A0 A1 A2 A3 A4 A5 A6 A7 A8 A9 A-0 A-1 A-2 A-3 A-4 A-5 A-6 A-7 A-8 A-9 B0 B1 B2 B3 B4 B5 B6 B7 B8 ...