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Since one in about every 6,400 hydrogen atoms is deuterium, a 50-kilogram (110 lb) human containing 32 kilograms (71 lb) of body water would normally contain enough deuterium (about 1.1 grams or 0.039 ounces) to make 5.5 grams (0.19 oz) of pure heavy water, so roughly this dose is required to double the amount of deuterium in the body. A loss ...
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Deuterium thus has about twice the atomic mass as 1 H. Heavy water consists of water molecules with two deuterium atoms instead of the two 1 H atoms. The hydrogen in normal water is about 99.97% 1 H (by weight). [2] The production of heavy water involves isolating and removing deuterium-containing isotopologues within natural water.
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Thus, deuterium accounts for about 0.0156% by number (0.0312% by mass) of all hydrogen in the ocean: 4.85 × 10 13 tonnes of deuterium – mainly as HOD (or 1 HO 2 H or 1 H 2 HO) and only rarely as D 2 O (or 2 H 2 O) (Deuterium Oxide, also known as Heavy Water)– in 1.4 × 10 18 tonnes of water.
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