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However, if data is a DataFrame, then data['a'] returns all values in the column(s) named a. To avoid this ambiguity, Pandas supports the syntax data.loc['a'] as an alternative way to filter using the index. Pandas also supports the syntax data.iloc[n], which always takes an integer n and returns the nth value, counting from 0. This allows a ...
A plus sign in an otherwise empty cell breaks default numerical sorting of a column. That is if the cell is one of the first 5 cells in the column. You can also use 2 columns for a range if you want to sort by either the lower or upper range. If you want the upper range to sort best all cells need to be filled in with numbers.
In addition to sorting them under "Mac" and "Mc" respectively or choosing to sort them both under "Mac", it is known for Mc/Mac names to be placed in separate position before M. [4] Sorting both under "Mc" is generally avoided as it can cause issues with names that do not contain the prefix (such as Macclesfield or Macey).
Such a component or property is called a sort key. For example, the items are books, the sort key is the title, subject or author, and the order is alphabetical. A new sort key can be created from two or more sort keys by lexicographical order. The first is then called the primary sort key, the second the secondary sort key, etc.
Timsort is a stable sorting algorithm (order of elements with same key is kept) and strives to perform balanced merges (a merge thus merges runs of similar sizes). In order to achieve sorting stability, only consecutive runs are merged. Between two non-consecutive runs, there can be an element with the same key inside the runs.
See Help:Sortable tables#Numerical sorting problems and meta:Help:Sorting#Sort modes Equal rank If you simply code as the second parameter an indicator that two items are equally ranked, e.g. "4=", the template interpreter will treat this as an additional parameter (i.e. parameter 4, which it will then not use).
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Recursively sort the "equal to" partition by the next character (key). Given we sort using bytes or words of length W bits, the best case is O(KN) and the worst case O(2 K N) or at least O(N 2) as for standard quicksort, given for unique keys N<2 K, and K is a hidden constant in all standard comparison sort algorithms including