Search results
Results from the WOW.Com Content Network
A right trapezoid (also called right-angled trapezoid) has two adjacent right angles. [13] Right trapezoids are used in the trapezoidal rule for estimating areas under a curve. An acute trapezoid has two adjacent acute angles on its longer base edge. An obtuse trapezoid on the other hand has one acute and one obtuse angle on each base.
A right trapezoid is a trapezoid that has two pairs of adjacent sides that are perpendicular. Each of the four maltitudes of a quadrilateral is a perpendicular to a side through the midpoint of the opposite side.
A right triangle ABC with its right angle at C, hypotenuse c, and legs a and b,. A right triangle or right-angled triangle, sometimes called an orthogonal triangle or rectangular triangle, is a triangle in which two sides are perpendicular, forming a right angle (1 ⁄ 4 turn or 90 degrees).
By applying the Pythagorean theorem to the right triangle AWP, and observing that WP = AZ, it follows that A P 2 = A W 2 + W P 2 = A W 2 + A Z 2 {\displaystyle AP^{2}=AW^{2}+WP^{2}=AW^{2}+AZ^{2}} and by a similar argument the squares of the lengths of the distances from P to the other three corners can be calculated as
Brahmagupta's theorem states that for a cyclic orthodiagonal quadrilateral, the perpendicular from any side through the point of intersection of the diagonals bisects the opposite side. [ 3 ] If an orthodiagonal quadrilateral is also cyclic, the distance from the circumcenter (the center of the circumscribed circle) to any side equals half the ...
To draw the circumcircle, draw two perpendicular bisectors p 1, p 2 on the sides of the bicentric quadrilateral a respectively b. The perpendicular bisectors p 1, p 2 intersect in the centre O of the circumcircle C R with the distance x to the centre I of the incircle C r. The circumcircle can be drawn around the centre O.
A frustum's axis is that of the original cone or pyramid. A frustum is circular if it has circular bases; it is right if the axis is perpendicular to both bases, and oblique otherwise. The height of a frustum is the perpendicular distance between the planes of the two bases.
An equivalent condition is that the bimedians of the quadrilateral (the diagonals of the Varignon parallelogram) are perpendicular. [ 3 ] A convex quadrilateral with diagonal lengths p {\displaystyle p} and q {\displaystyle q} and bimedian lengths m {\displaystyle m} and n {\displaystyle n} is equidiagonal if and only if [ 4 ] : Prop.1