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The longer side of a rectangle should be on the side BC. ~~~~~ A golden rectangle is a rectangle whose side lengths are in the golden ratio, 1 : (1 + √5) / 2 . If the short side of a rectangle is x then the longer side is x * [(1 + √5) / 2] Find angles B and C using the law of cosines. Use this formula to calculate the sides of a rectangle:
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The golden rectangle is inscribed in a circle with a radius of 10cm. Find the area of that rectangle. The ratio of the sides a and b of the golden rectangle is calculated by the upper formula. Because the ratio of the sides of this rectangle is constant, so must be the ratio of the angles that these sides form with rectangle's diagonal!
A Golden Rectangle is one where the sides are in proportion of 1 : Phi . Where Phi = (1 + sqrt 5 ) / 2 ≈ 1.618
The length of the diagonal of the rectangle = the diameter of the circle = 10 . So....using the P Theorem. L^2 + W^2 = 10^2 (1)
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The rectangle with area 4 is sharing its width with the rectangle with unknown area. Let this value be \(z\) The rectangle with area 5 is sharing its length with the rectangle with unknown area. Let this value be \(w\) If we set up and equation for each rectangle, we get the following: Bottom left rectangle: \(xy = 3\) Bottom right rectangle ...
The perimeter of a rectangle is $40,$ and the length of one of its diagonals is $10 \\sqrt{2}.$ Find the area of the rectangle.
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A rectangle contains a strip of width $1,$ as shown below. Find the area of the strip.