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The molecular molar mass consists of the atomic masses of each atom.. Sodium hydroxide is #"NaOH"#.Thus, its molar mass involves:
Question: What mass of sodium hydroxide (NaOH, molar mass = 40.0 g.mol-1) is needed to make 100.0 mL of a 0.125 M NaOH solution? OA) 0.0500 g OB) 0.500 g OC) 3.13 g OD) 5.00 g Show transcribed image text
Question: 4. Calculate the expected concentration of the sodium hydroxide solution. The molar mass of NaOH is 39.997 g/mol. 5. Calculate and record the expected mass of benzoic acid required to react with 20.00 mL of a 0.100 M sodium hydroxide solution. Record the mass of benzoic acid using three significant digits to reference later.
The units of molar mass are grams per mole, or g/mol. Molar mass allows scientist to convert between moles and grams, or vice versa. Answer and Explanation: 1 The molar mass of sodium hydroxide equals 39.997 g/mol.
Question 41 (Mandatory) (1 point) What mass of sodium hydroxide (NaOH, molar mass = 40.0 g.mol-1) is needed to make 100.0 mL of a 0.125 M NaOH solution? Data sheet and Periodic Table 0.500 g 5.00 g 0.0500 g 03.13 g
Suppose you are standardizing a sodium hydroxide solution with KHP (molar mass=204.2 g/mol) according to the equation KHP + NaOH + H2O + NaKP You prepare the standard solution from 0.291 g of KHP in 250.0 mL of water. You then require 8.44 mL of NaOH solution to complete the titration What is the concentration of the NaOH solution? Type answer
Calculate the molar mass of sodium hydroxide. Select the correct answer below: 24.00 g/mol 38.99 g/mol 40.0 g/mol 56,0 g/mol There are molecules in 59.0 grams of SF6 Select the correct answer below: 2.43 x 1023molecules O 3.55 x 1025 molecules O 8.80 x 1025 molecules O 1.49 x 1024molecules QUESTION 18.1 POINT How many re-bonds are there in the ...
For the oxalic acid (MM= 90,03 g/mol; ME = 45,01 g/eq) is necessary a double quantity of moles of NaOH, since oxalic acid is biprotic (1 eq = 2 mol), or (that is the same) the Equivalent Mass of the oxalic acid is the half of the Molecular Mass .
When a 6.16 g sample of solid sodium hydroxide (molar mass 40.00 g / mol) dissolves in 100.0 g water in a coffee cup calorimeter, the temperature rises from 21.6 to 37.8 ∘ C. Calculate Δ H (in kJ / molNaOH) for the solution process. Assume that the specific heat of the solution is the same as that of pure water.
"160 g" Molarity is given by "Molarity" = "Moles of solute"/"Volume of solution (in litres)" "2.00 M" = "n"/"2.00 L" "n = 4.00 mol" Molar mass of "NaOH" is "40 g/mol" So, mass of "NaOH" needed is 4.00 cancel"mol" × 40\ "g"/cancel"mol" = "160 g"