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At least 3,300 nuclides have been experimentally characterized [1] (see List of radioactive nuclides by half-life for the nuclides with decay half-lives less than one hour). A nuclide is defined conventionally as an experimentally examined bound collection of protons and neutrons that either is stable or has an observed decay mode .
In nuclear physics and nuclear chemistry, a nuclear reaction is a process in which two nuclei, or a nucleus and an external subatomic particle, collide to produce one or more new nuclides. Thus, a nuclear reaction must cause a transformation of at least one nuclide to another.
Likewise, nuclides with the same neutron excess (N − Z) are called isodiaphers. [4] The name isotone was derived from the name isotope to emphasize that in the first group of nuclides it is the number of neutrons (n) that is constant, whereas in the second the number of protons (p). [5]
Only nuclides are considered to decay and produce radioactivity. [55]: 568 Nuclides can be stable or unstable. Unstable nuclides decay, possibly in several steps, until they become stable. There are 251 known stable nuclides. The number of unstable nuclides discovered has grown, with about 3000 known in 2006. [55]
The only stable nuclides having an odd number of protons and an odd number of neutrons are hydrogen-2, lithium-6, boron-10, nitrogen-14 and (observationally) tantalum-180m. This is because the mass–energy of such atoms is usually higher than that of their neighbors on the same isobaric chain, so most of them are unstable to beta decay .
Stable even–even nuclides number as many as three isobars for some mass numbers, and up to seven isotopes for some atomic numbers. Conversely, of the 251 known stable nuclides, only five have both an odd number of protons and odd number of neutrons: hydrogen-2 , lithium-6, boron-10, nitrogen-14, and tantalum-180m.
First proposed in 1972 by Meldner, such a reaction might enable the production of macroscopic quantities of superheavy elements within the island of stability; [1] the role of fission in intermediate superheavy nuclides is highly uncertain, and may strongly influence the yield of such a reaction. [88] This chart of nuclides used by the Japan ...
To calculate the binding energy we use the formula Z (m p + m e) + N m n − m nuclide where Z denotes the number of protons in the nuclides and N their number of neutrons. We take m p = 938.272 0813 (58) MeV/c 2, m e = 0.510 998 9461 (30) MeV/c 2 and m n = 939.565 4133 (58) MeV/c 2. The letter A denotes the sum of Z and N (number