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The centimetre (SI symbol: cm) is a unit of length in the metric system equal to 10 −2 metres ( 1 / 100 m = 0.01 m). To help compare different orders of magnitude, this section lists lengths between 10 −2 m and 10 −1 m (1 cm and 1 dm). 1 cm – 10 millimeters; 1 cm – 0.39 inches; 1 cm – edge of a square of area 1 cm 2
The corresponding metric inch of 25 millimetres (0.984 in) was used for pin spacing in Soviet microchips, which were often cloned from Western designs but scaled down slightly from US customary inches to metric inches. This led to incompatibility issues in the Soviet computer market. [9]
SD g/mm 2 is the sectional density in grams per square millimeters; m g is the mass of the projectile in grams; d mm is the diameter of the projectile in millimeters; For example, a small arms bullet with a mass of 10.4 grams (160 gr) and having a diameter of 6.70 mm (0.264 in) has a sectional density of: 4 · 10.4 / (π·6.7 2) = 0.295 g/mm 2
Cross-sectional area of a mechanical pencil lead (0.5-0.7 mm in diameter) [16] 10 −6: 1 square millimetre (mm 2) 1–2 mm 2: Area of a human fovea [17] 2 mm 2: Area of the head of a pin: 10 −5 30–50 mm 2: Area of a 6–8 mm hole punched in a piece of paper by a hole punch [18] 10 −4: 1 square centimetre (cm 2) 290 mm 2: Area of one side ...
The nanoacre is a unit of real estate on a very-large-scale integration (VLSI) chip equal to 0.00627264 sq in (4.0468564224 mm 2) or the area of a square of side length 0.0792 in (2.01168 mm). VLSI nanoacres have similar total costs to acres in Silicon Valley. [29]
Centimeters (cm) are avoided as they cause confusion when reading plans. For example, the length two and a half meters is usually recorded as 2500 mm or 2.5 m; it would be considered non-standard to record this length as 250 cm. [12] [13]
Technical publications by industry publishers and American automakers often give engine displacements in cubic inches as well as cubic centimeters (which are equivalent to milliliters), or liters. [66] [67] For example, the specifications for the Dodge SRT-8 6.1 L Hemi state the displacement as 370 cubic inches (6,100 cm 3). [68]
If using the metric unit meters for distance and the imperial unit inches for target size, one has to multiply by a factor of 25.4, since one inch is defined as 25.4 millimeters. distance in meters = target in inches angle in mrad × 25.4 {\displaystyle {\text{distance in meters}}={\frac {\text{target in inches}}{\text{angle in mrad}}}\times 25.4}