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  2. Fraction - Wikipedia

    en.wikipedia.org/wiki/Fraction

    A unit fraction is a common fraction with a numerator of 1 (e.g., ⁠ 1 / 7 ⁠). Unit fractions can also be expressed using negative exponents, as in 21, which represents 1/2, and 22, which represents 1/(2 2) or 1/4. A dyadic fraction is a common fraction in which the denominator is a power of two, e.g. ⁠ 1 / 8 ⁠ = ⁠ 1 / 2 3 ⁠.

  3. Partial fraction decomposition - Wikipedia

    en.wikipedia.org/wiki/Partial_fraction_decomposition

    In algebra, the partial fraction decomposition or partial fraction expansion of a rational fraction (that is, a fraction such that the numerator and the denominator are both polynomials) is an operation that consists of expressing the fraction as a sum of a polynomial (possibly zero) and one or several fractions with a simpler denominator. [1]

  4. Help:Displaying a formula - Wikipedia

    en.wikipedia.org/wiki/Help:Displaying_a_formula

    Download as PDF; Printable version; ... one has to add 1= just before the formula for avoiding confusion with the template syntax; ... < math > x ^ 2 + y ^ 2 + z ^ 2 ...

  5. Continued fraction - Wikipedia

    en.wikipedia.org/wiki/Continued_fraction

    where c 1 = ⁠ 1 / a 1 ⁠, c 2 = ⁠ a 1 / a 2 ⁠, c 3 = ⁠ a 2 / a 1 a 3 ⁠, and in general c n+1 = ⁠ 1 / a n+1 c n ⁠. Second, if none of the partial denominators b i are zero we can use a similar procedure to choose another sequence { d i } to make each partial denominator a 1:

  6. Fractional calculus - Wikipedia

    en.wikipedia.org/wiki/Fractional_calculus

    [5] [6] [7] Oliver Heaviside introduced the practical use of fractional differential operators in electrical transmission line analysis circa 1890. [8] The theory and applications of fractional calculus expanded greatly over the 19th and 20th centuries, and numerous contributors have given different definitions for fractional derivatives and ...

  7. Solving quadratic equations with continued fractions - Wikipedia

    en.wikipedia.org/wiki/Solving_quadratic...

    By applying the fundamental recurrence formulas we may easily compute the successive convergents of this continued fraction to be 1, 3/2, 7/5, 17/12, 41/29, 99/70, 239/169, ..., where each successive convergent is formed by taking the numerator plus the denominator of the preceding term as the denominator in the next term, then adding in the ...

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