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The area of a triangle is its half of the product of the base times the height (length of the altitude). For a triangle A B C {\displaystyle \triangle ABC} with opposite sides a , b , c , {\displaystyle a,b,c,} if the three altitudes of the triangle are called h a , h b , h c , {\displaystyle h_{a},h_{b},h_{c},} the area is:
The process of drawing the altitude from a vertex to the foot is known as dropping the altitude at that vertex. It is a special case of orthogonal projection. Altitudes can be used in the computation of the area of a triangle: one-half of the product of an altitude's length and its base's length (symbol b) equals the triangle's area: A = h b /2 ...
The area of a triangle can be demonstrated, for example by means of the congruence of triangles, as half of the area of a parallelogram that has the same base length and height. A graphic derivation of the formula T = h 2 b {\displaystyle T={\frac {h}{2}}b} that avoids the usual procedure of doubling the area of the triangle and then halving it.
The Kepler triangle is a right triangle whose sides are in geometric progression. If the sides are formed from the geometric progression a, ar, ar 2 then its common ratio r is given by r = √ φ where φ is the golden ratio. Its sides are therefore in the ratio 1 : √ φ : φ. Thus, the shape of the Kepler triangle is uniquely determined (up ...
The triangle shown is the unique isosceles triangle for which there are exactly two perpendicular quadrisections. [ 1 ] In triangle geometry , the Bernoulli quadrisection problem asks how to divide a given triangle into four equal-area pieces by two perpendicular lines.
The opening of the dark-blue square by a disk, resulting in the light-blue square with round corners. In mathematical morphology, opening is the dilation of the erosion of a set A by a structuring element B:
By Barbier's theorem, the body's perimeter is exactly π times its width, but its area depends on its shape, with the Reuleaux triangle having the smallest possible area for its width and the circle the largest. Every superset of a body of constant width includes pairs of points that are farther apart than the width, and every curve of constant ...
The area of a triangle is formulated as the half product of base and height and the sine of an angle. Because all of the angles of an equilateral triangle are 60°, the formula is as desired. [citation needed] A version of the isoperimetric inequality for triangles states that the triangle of greatest area among all those with a given perimeter ...