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The standard molar entropy of a gas at STP includes contributions from: [2] The heat capacity of one mole of the solid from 0 K to the melting point (including heat absorbed in any changes between different crystal structures). The latent heat of fusion of the solid. The heat capacity of the liquid from the melting point to the boiling point.
The ideal gas equation can be rearranged to give an expression for the molar volume of an ideal gas: = = Hence, for a given temperature and pressure, the molar volume is the same for all ideal gases and is based on the gas constant: R = 8.314 462 618 153 24 m 3 ⋅Pa⋅K −1 ⋅mol −1, or about 8.205 736 608 095 96 × 10 −5 m 3 ⋅atm⋅K ...
Another example of the apparent molar volume of the second component is less than its molar volume as a pure substance is the case of ethanol in water. For example, at 20 mass percents ethanol, the solution has a volume of 1.0326 liters per kg at 20 °C, while pure water is 1.0018 L/kg (1.0018 cc/g). [5]
Note that the especially high molar values, as for paraffin, gasoline, water and ammonia, result from calculating specific heats in terms of moles of molecules. If specific heat is expressed per mole of atoms for these substances, none of the constant-volume values exceed, to any large extent, the theoretical Dulong–Petit limit of 25 J⋅mol ...
Reaction stoichiometry describes the 2:1:2 ratio of hydrogen, oxygen, and water molecules in the above equation. The molar ratio allows for conversion between moles of one substance and moles of another. For example, in the reaction 2 CH 3 OH + 3 O 2 → 2 CO 2 + 4 H 2 O. the amount of water that will be produced by the combustion of 0.27 moles ...
V m = 10.7316 × 519.67 / 14.696 = 379.48 ft 3 /lbmol at 60 °F and 14.696 psi (or about 0.8366 ft 3 /gram mole) V m = 10.7316 × 519.67 / 14.730 = 378.61 ft 3 /lbmol at 60 °F and 14.73 psi Technical literature can be confusing because many authors fail to explain whether they are using the ideal gas constant R , or the specific gas constant R s .
The standard state of a material (pure substance, mixture or solution) is a reference point used to calculate its properties under different conditions.A degree sign (°) or a superscript Plimsoll symbol (⦵) is used to designate a thermodynamic quantity in the standard state, such as change in enthalpy (ΔH°), change in entropy (ΔS°), or change in Gibbs free energy (ΔG°).
Note that the form of this formula as given is a fit to the Clausius–Clapeyron equation, which is a good theoretical starting point for calculating saturation vapor pressures: log 10 (P) = −(0.05223) a / T + b , where P is in mmHg, T is in kelvins, a = 38324, and b = 8.8017.