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7. object is the base class from which you inherit when creating a new-style class in Python 2. It's not necessary to do this in Python 3.x, however. New-style classes are the default. In Python 3, all classes still inherit from object. In addition, "the type of word that object is" is an identifier.
1. When comparing instances of objects, the __cmp__ function is called. If the == operator is not working for you by default, you can always redefine the __cmp__ function for the object. Edit: As has been pointed out, the __cmp__ function is deprecated since 3.0. Instead you should use the “rich comparison” methods.
So basically, type(var) is <class 'a type'>. Example: <class 'int' But, when var is a class, it will appear something like <class '__main__.classname'>. So we split the string into <class '__main__ and we compare using if, if the string fit perfectly then it's a class. answered Feb 7, 2022 at 13:49. Kirro Smith.
Use one line, s = json.dumps(obj, default=lambda x: x.__dict__), to serialize object's instance variables (self.value1, self.value2, ...). Its the simplest and the most straight forward way. It will serialize nested object structures. The default function is called when any given object is not directly serializable.
dir() is exactly what I was looking for when I Googled 'Python object list attributes' -- A way to inspect an instance of an unfamiliar object and find out what it's like. – JDenman6 Commented Aug 21, 2020 at 15:14
To get things shorter, name your cleanup function close and use contextlib.closing, in which case you can either use the unmodified Package class via with contextlib.closing(Package(...)) or override its __new__ to the simpler. class Package(object): def __new__(cls, *args, **kwargs):
4. Yes, classes (and functions, and modules, and basically everything) in Python are objects, too. The difference lies in their types: class Foo(object): pass. print type(Foo) print type(Foo()) To see they're both objects, you can check that they both have attributes: print dir(Foo)
Consider class Foo(object): def __init__(self, arg): super(Foo, self).__init__() self.arg = arg Basic as it gets. If I do foo = Foo(3) bar = copy(foo) print(foo.arg) # 3 print(bar.arg) # <__main__.Foo object at ...> Meaning that your copy function is broken for even the most basic of classes. Again, it's a neat trick (hence no DV), but not an ...
7. I am just starting to learn python and am getting confused about how to pass an instance of an object as an argument for a function, below is a little bit of code I made for practice and the basic idea is that there is one garage, this garage contains no cars, and you can add cars to the garage and view their details. class Garage: cars = []
The answer, in a few words. In your example, itsProblem is a local variable. Your must use self to set and get instance variables. You can set it in the __init__ method. Then your code would be: def __init__(self): self.itsProblem = "problem". But if you want a true class variable, then use the class name directly: itsProblem = "problem".