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Miners also use it as a unit of area equal to 6 feet square (3.34 m 2) in the plane of a vein. [2] In Britain, it can mean the quantity of wood in a pile of any length measuring 6 feet (1.8 m) square in cross section. [2] In Central Europe, the klafter was the corresponding unit of comparable length, as was the toise in France.
150 feet (46 m) Max. depth: 68 m (223 ft) ... The shortest distance across the strait, at approximately 20 miles (32 kilometres), is from the South Foreland, ...
15.24 meters – width of an NBA basketball court (50 feet) 18.44 meters – distance between the front of the pitcher's rubber and the rear point of home plate on a baseball field (60 feet, 6 inches) [126] 20 meters – length of cricket pitch (22 yards) [127] 27.43 meters – distance between bases on a baseball field (90 feet)
Go around’: Pilots who came within 150 feet of a crash share how they deftly averted disaster. Pete Muntean and Marnie Hunter, CNN. September 13, 2024 at 3:38 PM.
The basic unit of length in the imperial and U.S. customary systems is the yard, defined as exactly 0.9144 m by international treaty in 1959. [2] [5] Common imperial units and U.S. customary units of length include: [6] thou or mil (1 ⁄ 1000 of an inch) inch (25.4 mm) foot (12 inches, 0.3048 m) yard (3 feet, 0.9144 m)
A nautical mile is a unit of length used in air, marine, and space navigation, and for the definition of territorial waters. [2] [3] [4] Historically, it was defined as the meridian arc length corresponding to one minute ( 1 / 60 of a degree) of latitude at the equator, so that Earth's polar circumference is very near to 21,600 nautical miles (that is 60 minutes × 360 degrees).
In addition to the yardland, Old and Middle English both used their forms of "yard" to denote the surveying lengths of 15 feet (4.6 m) or 16.5 feet (5.0 m), used in computing acres, a distance now usually known as the "rod". [5] A unit of three English feet is attested in a statute of c. 1300 , but there it is called an ell (ulna, lit.
The first equation shows that, after one second, an object will have fallen a distance of 1/2 × 9.8 × 1 2 = 4.9 m. After two seconds it will have fallen 1/2 × 9.8 × 2 2 = 19.6 m; and so on. On the other hand, the penultimate equation becomes grossly inaccurate at great distances.